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enyata [817]
3 years ago
13

A photon has an energy of 5.53 à 10¯17 j. what is its frequency in s¯1?

Physics
1 answer:
Butoxors [25]3 years ago
5 0
<span>energy is directly proportional fo frequency 
as in blue photons are more energetic than red photons 
so 
E = h * f 
look up h (Planck's constant) 
plug and play!</span><span>
</span>
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Which type of radioactive decay results in no change in mass number and atomic number for the starting nucleus?
Volgvan

Answer:

Gamma Rays

Explanation:

For the starting nucleus, the gamma rays is the type of radioactive decay results in no change in mass number and atomic number. This is only due to the fact that gamma rays don't have any mass and also don't have any kind of electric charge. So after decaying it shows no sign of change in atomic number because neither the mass has changed nor the charge.

7 0
3 years ago
Select the correct answer.
Marianna [84]

Answer:

A

Explanation:

According to Newton's second law, acceleration is directly proportional to the net force. As the acceleration increases (when mass is constant), the net force increases. This is represented in the following formula.

f = ma

a =  \frac{f}{m}

a = acceleration

f = force

m = mass

6 0
4 years ago
An AC generator consists of 20 circular loops of wire with an area of 75 cm2. It has a maximum induced voltage of 24 V. If its a
Monica [59]

Faraday's law allows us to find the magnetic field that produces the emf in the rotating system is:

  • The magnetic field is:  B = 0.424 T

Faraday's law of induction states that when the magnetic flux changes in time, an induced electromotive force is produced.

            fem = - \frac{d \Phi_B }{dt}  

where fem is the induced electromotive force and Ф the flux,

The magnetic flux is the scalar product of the field and the area.

           \Phi_B = B . A = B A  \ cos \theta  

In this case we have several turns, so the expression remains.

           fem = - N B A \ \frac{d cos \theta}{dt}  

Indicate that the turns rotate at a constant frequency, therefore we can use the uniform rotational motion ratio.

           

           θ = w t

We substitute

 

         fem = - N B A \ \frac{d \ cos \ wt}{dt}\\fem =  N B A w sin \ wt

the maximum induced electromotive force occurs when the sine function is ±1

          fem = N B A w

They indicate that the fem = 24 V, the number of the turn is N = 20, the area is A = 75 cm² = 75 10⁻⁴ m² and the frequency f = 60 Hz

Frequency and angular velocity are related.

           w = 2π f

We substitute.

           fem = N B A 2π f

           B = \frac{fem }{2 \pi \ NA \ f}  

Let's calculate.

         B= \frac{24 }{2\pi \ 20 \ 75 \ 10^{-4} 60}B = 24 / 2pi 20 75 10-4 60

         B = 0.424 T

In conclusion, using Faraday's law we can find the magnetic field that produces the emf in the rotating system is:

  • The magnetic field is; B = 0.424 T

Learn more about Faraday's law here:  brainly.com/question/24617581

8 0
3 years ago
What is the energy stored in the 10.5 μ F 10.5 μF capacitor of a heart defibrillator charged to 8250 V ?
Kay [80]

Answer:

356.33 J

Explanation:

Energy: This can be defined as the ability or the capacity to do work. The S.I unit of Energy is Joules (J).

The Energy stored in a capacitor = 1/2CV²

E = 1/2CV².............................. Equation 1.

Where E = Energy stored in a capacitor, C = capacitance of the capacitor, V = potential difference across the plates of the capacitor.

Given: C = 10.5 μF  = 10.5×10⁻⁶ F, V = 8250 V.

Substitute into equation 1

E = 1/2(10.5×10⁻⁶)(8250)²

E = 357.33 J.

Thus the energy stored in the defibrillator = 356.33 J

3 0
4 years ago
Un cuerpo recibe una fuerza de 100N y produce una aceleracion de 2 m/s² determine la masa del cuerpo
kykrilka [37]

Answer:

The mass of the body is 50 kg.

Explanation:

We have,

Force acting on a body is 100 N

Acceleration of the body is 2 m/s²

It is required to find the mass of the body. The force acting on a body is given by :

F = ma

m=\dfrac{F}{a}\\\\m=\dfrac{100}{2}\\\\m=50\ kg

So, the mass of the body is 50 kg.

3 0
3 years ago
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