A rancher wants to enclose a rectangular field with 220 ft of fencing.
One side is a river and will not require a fence.
What is the maximum area that can be enclosed?
:
The field requires only 3 sides of fence, therefore
L + 2W = 220
L = (220-2W); we can use this for substitution in the Area equation
:
Area
A = L*W
replace L with (220-2W)
A = W(220-2W)
A = -2W^2 + 220W
A quadratic equation, max A occurs at the axis of symmetry, x = -b/(2a)
In this equation
W = %28-220%29%2F%282%2A-2%29
W = 55 ft is the width for max area
:
Find the max area
A = -2(55^2) + 220(55)
A = -2(3025) + 12100
A = 6050 sq/ft is the max area
:
:
Confirm this with the dimensions calculated; 110 * 55 = 6050
You already have the answer
Answer:
x=4
Step-by-step explanation:
to get rid of the square root on the right you square both sides so
2x+8=x^2
Then bring
2x+8
to the left so you have 0=(x^2)−2x+8
Now you can do the quadratic formula to find the zeroes
Answer: C
Step-by-step explanation:
thank me later
10*10=100
100*132.71=13271
