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Aneli [31]
3 years ago
8

A hacker is trying to guess someone's password. the hacker knows (somehow) that the password is 6 digits long, and that each dig

it cound be a number between 0 and 8. assume that the hacker makes random guesses. what is the probability that the hacker guesses the password on his first try? round to four decimal places.
Mathematics
1 answer:
weqwewe [10]3 years ago
8 0
The amount of passwords possible is:
{8}^{6}  = 262144
Since he only tries once for the first try we get:
{262144}^{ - 1}
Thus there is a:
0.0001\%
Chance he will guess the password on his first try.
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3. Angles X and Y have a sum of 159 degrees. Angle X is 43 degrees smaller than angle Y.
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\underline{\underline{\large\bf{Solution:-}}}\\

\longrightarrowSince angle X and Y have a sum of 159

\implies \bf Y + X= 159 \_\_\_\_(1)

\longrightarrowSince X is 43 degrees smaller than Y , so subtracting X from Y would give 43 , therefore equation will be written as -

\implies \bf Y - X = 43 \_\_\_\_(2)

<u>Adding Equation (1) and (2) </u>

\begin{gathered}\\\implies\quad \sf Y+X+Y-X = 159+43 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf Y+Y + X-X = 202 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf 2Y = 202 \\\end{gathered}

\begin{gathered}\\\implies\quad \sf Y = \frac{202}{2} \\\end{gathered}

\begin{gathered}\\\implies\quad \boxed{\sf {Y = 101 }} \\\end{gathered}

<u>Putting Y in eq (1)</u>

\begin{gathered}\\\implies\quad \sf X + 101 = 153 \\\end{gathered}

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