Question

A car travels 3 km north, then turns and travels 4 km west. What is the car's displacement?

Answer 1

Explanation:

Displacement = Shortest path Travelled from starting point to final point..

Displacement formula = Final position - Initial position

= 7km - 3km

= 4km

^Displacement is 4km

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Tq..

Answer 2

"Displacement" is the straight-line distance and direction between the start-point and the end-point, regardless of what route was taken to get there.

If you draw a picture of how this car traveled, you'll see that it drove along two legs of a right triangle. I'm guessing the driver probably decided to stay on the streets, instead of driving the STRAIGHT line across people's lawns to get to the grocery store.  if a BIRD wanted to make the same trip, it would just fly in a straight line, straight over houses and yards.

The bird would fly along the hypotenuse of the right triangle.  The distance would be  √(3² + 4²).

That's √(9 + 16), which is √(25), and that's 5 km .

'Displacement' is a vector, and it also needs a direction.

After driving 3km north and 4km west, you are 5km roughly Northwest of where you started from.  (actually 53.1° west of north)

The car's displacement is 5 km , 53.1° west of north,

or 5 km at an azimuth of 306.9° .