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taurus [48]
3 years ago
14

A car travels 3 km north, then turns and travels 4 km west. What is the car's displacement?

Physics
2 answers:
Olin [163]3 years ago
5 0

Explanation:

Displacement = Shortest path Travelled from starting point to final point..

Displacement formula = <em>Final</em><em> </em><em>position</em><em> </em><em>-</em><em> </em><em> </em><em>Initial</em><em> </em><em>position</em>

= 7km - 3km

= 4km

^Displacement is 4km

<em>If</em><em> </em><em>this</em><em> answer</em><em> helps</em><em> you</em><em> plz</em><em> mark</em><em> as</em><em> brainlist</em><em>.</em><em>.</em>

<em>Tq</em><em>.</em><em>.</em>

Karolina [17]3 years ago
4 0

"Displacement" is the straight-line distance and direction between the start-point and the end-point, regardless of what route was taken to get there.

If you draw a picture of how this car traveled, you'll see that it drove along two legs of a right triangle. I'm guessing the driver probably decided to stay on the streets, instead of driving the STRAIGHT line across people's lawns to get to the grocery store.  if a BIRD wanted to make the same trip, it would just fly in a straight line, straight over houses and yards.

The bird would fly along the hypotenuse of the right triangle.  The distance would be  √(3² + 4²).

That's √(9 + 16), which is √(25), and that's 5 km .

'Displacement' is a vector, and it also needs a direction.

After driving 3km north and 4km west, you are 5km roughly Northwest of where you started from.  (actually 53.1° west of north)

The car's displacement is 5 km , 53.1° west of north,

or <em>5 km at an azimuth of 306.9°</em> .

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Answer:

a) -2.038 m/s²

b) 40.33 mph

c) 312.5 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-25^2}{2\times 150}\\\Rightarrow a=-2.083\ m/s^2

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