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2 years ago

A car travels 3 km north, then turns and travels 4 km west. What is the car's displacement?

Physics

2 answers:

Olin [163]2 years ago

5 0

Explanation:

Displacement = Shortest path Travelled from starting point to final point..

Displacement formula = Final position - Initial position

= 7km - 3km

= 4km

^Displacement is 4km

If this answer helps you plz mark as brainlist..

Tq..

Karolina [17]2 years ago

4 0

"Displacement" is the straight-line distance and direction between the start-point and the end-point, regardless of what route was taken to get there.

If you draw a picture of how this car traveled, you'll see that it drove along two legs of a right triangle. I'm guessing the driver probably decided to stay on the streets, instead of driving the STRAIGHT line across people's lawns to get to the grocery store. if a BIRD wanted to make the same trip, it would just fly in a straight line, straight over houses and yards.

The bird would fly along the hypotenuse of the right triangle. The distance would be √(3² + 4²).

That's √(9 + 16), which is √(25), and that's 5 km .

'Displacement' is a vector, and it also needs a direction.

After driving 3km north and 4km west, you are 5km roughly Northwest of where you started from. (actually 53.1° west of north)

The car's displacement is 5 km , 53.1° west of north,

or 5 km at an azimuth of 306.9° .

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2 years ago

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The answer for the following problem is explained below.

Therefore the volume charge density of a substance (ρ) is 0.04 × $10^{-1}$ C.

Explanation:

Given:

radius (r) =2.1 cm = 2.1 × $10^{-2}$ m

height (h) =8.8 cm = 8.8 × $10^{-2}$ m

total charge (q) =6.1× $10^{-7}$ C

To solve:

volume charge density (ρ)

We know;

ρ =q ÷ v

volume of cylinder = π ×r × r × h

volume of cylinder =3.14 × 2.1 × 2.1 × $10^{-4}$ × 8.8 × $10^{-2}$

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ρ =q ÷ v

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Read 2 more answers

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B-QUANTITY

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2 years ago

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Answer:

Please check the attached file for the diagram

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