The answer is fish I’ve had this question before
Answer:

Explanation:
Gravitational potential energy is the energy an object possesses due to its position. It is calculated using the following formula:

Where <em>m</em> is the mass, <em>g</em> is the acceleration due to gravity, and <em>h</em> is the height.
The object has a mass of 8.72 kilograms. Assuming this occurs on Earth, the acceleration due to gravity is 9.8 meters per second squared. The object gains 446 Joules of potential energy.
Let's convert the units of Joules. This makes the process of canceling units simpler later on. 1 Joule is equal to 1 kilogram meter squared per second squared. The object gains 446 J, which is equal to 446 kg *m²/s².
- EP= 446 kg*m²/s²
- m= 8.72 kg
- g= 9.8 m/s²
Substitute the values into the formula.

Multiply on the right side of the equation.

We are solving for the height, so we must isolate the variable h. It is being multiplied by 85.456 kg*m/s². The inverse operation of multiplication is division, so we divide both sides by this value.


The units of kg*m/s² cancel, leaving meters as our unit.


The original measurements of mass and potential energy have 3 significant figures, so our answer must have the same.
For the number we calculated, that is the hundredths place. The 9 in the thousandths place to the right tells us to round the 1 up to a 2.

The object was lifted to a height of approximately <u>5.22 meters.</u>
Answer:
When there is no force acting on a body then a moving object move in a straight line with constant velocity and an object in rest stays in rest.
Explanation:
When there is no force acting on a body then a moving object move in a straight line with constant velocity and an object in rest stays in rest.
Answer:1
Explanation:
If
s=displacement
v=velocity of particle
a=acceleration of particle
acceleration can be written as rate of change of velocity
so 
multiply and divide by 




option 1 is correct
Answer:
(a) 81.54 N
(b) 570.75 J
(c) - 570.75 J
(d) 0 J, 0 J
(e) 0 J
Explanation:
mass of crate, m = 32 kg
distance, s = 7 m
coefficient of friction = 0.26
(a) As it is moving with constant velocity so the force applied is equal to the friction force.
F = 0.26 x m x g = 0.26 x 32 x 9.8 = 81.54 N
(b) The work done on the crate
W = F x s = 81.54 x 7 = 570.75 J
(c) Work done by the friction
W' = - W = - 570.75 J
(d) Work done by the normal force
W'' = m g cos 90 = 0 J
Work done by the gravity
Wg = m g cos 90 = 0 J
(e) The total work done is
Wnet = W + W' + W'' + Wg = 570.75 - 570.75 + 0 = 0 J