Answer:
What is the formula for elevation in boiling point?
Explanation:
The elevation in boiling point (ΔTb) is proportional to the concentration of the solute in the solution. It can be calculated via the following equation. Where, i is the Van't Hoff factor.
...
Boiling Point Elevation Formula.
Solvent Kb value (in oC.kg.mol-1)
Chloroform 3.63
Benzene 2.53
Answer:
pA = 0.095 atm
pB = 0.303 atm
Explanation:
Step 1: the reaction
AB(s) ⇔ A(g) + B(g)
Kp = pA * pB
⇒ with Kp = equilibrium constant
Kp = 0.126 * 0.23 ⇒ Kp = 0.02898
Since the container will be compressed to half of its original volume, means that he pressure will be doubled.
⇒pA = 0.252
⇒pB =0.46
To establish this equilibrium, each pressure has to be lowered by x
⇒pA = 0.252 - x
⇒pB = 0.46 - x
Kp = 0.02898 = (0.252 - x)(0.46-x)
0.02898 = 0.11592 - 0.252x -0.46x + x²
-x² + 0.712x - 0.08694 = 0
D= b² - 4ac
⇒ D = 0.712² -4*(-1) *(-0.08694) = 0.506944 -0.34776 =0.159184
x = (-b ± √D)/2a
x = (-0.712 ± √0.159184)/(2*-1) = (-0.712 ± 0.398978696)/-2
x = 0.156510652 or x= 0.555489348
x = 0.555489348 is impossble or the pressure would be negative
x=0.156510652
pA =0.252 - 0.156510652 = 0.095489348 atm
pB = 0.46 - 0.156510652 = 0.303489348 atm
Answer:
False. The balanced equation should be
2KClO3-->2KCl + 3O2
it is a decomposition reaction.
Remark
The given thing on the right is a positron. The mass for these subatomic particles is considered to be 0. It's atomic number is 1 which means it is a blood relative of a proton.
So essentially what happens is that X is one space to the left on the periodic table. But let's solve this a little bit more formally.
Solution
y stays the same at 147. It is z that changes.
65 = z + 1 Subtract 1 from both sides.
64 = z
So the chemical with 64 as its position on the periodic table is
Gadolinium and the answer is C
Answer:
10.4664 grams of CO
Explanation:
Remark
There's a couple of things you must look out for in this question.
1. The use of the term atoms. There are 2 atoms in each mol of CO
2. You need to divide by 2 to find the number of molecules which will lead to moles.
<u>Step one</u>
Divide the number of atoms by 2
4.50 e^23 / 2 atoms = 2.25 * 10^23 molecules.
<u>Step Two</u>
Find the number of moles of CO
1 mol of anything is 6.02 * 10^23 molecules in this case
x = 2.25 * 10^23 molecules
1/x = 6.02 * 10^23/2.25 * 10 ^23 Cross multiply
1 * 2.25 * 10^23 = 6.02*10^23 * x Divide by 6.02 * 10^23
2.25 * 10 ^ 23 / 6.02 * 10^23 = x
x = .3738 moles of CO
<u>Step Three</u>
Find the gram molecular mass of CO
C = 12
O = 16
1 mole = 12 + 16 = 28 grams.
<u>Step Four</u>
Find the number of gram in 0.3738 mols
1 mol = 28 grams
0.3738 mol = x Cross multiply
x = 28 * 0.3738
x = 10.4664 grams
