The force would be 10.5 n given that mass of the soccer ball, m= 0.42 kg
Answer:
The molality is 0.504 molal
Explanation:
Step 1: Data given
Mass of NaCl = 25.00 grams
Molar mass NaCl = 58.44 g/mol
Mass of water = 850.0grams
Step 2: Calculate moles NaCl
Moles NaCl = mass NaCl / molar mass NaCl
Moles NaCl = 25.0 grams / 58.44 g/mol
Moles NaCl = 0.428 moles
Step 3: Calculate molality
Molality = moles NaCl / mass H2O
Molality = 0.428 moles / 0.850 kg
Molality = 0.504 molal
The molality is 0.504 molal
Answer:
a vanilla milkshake
Explanation:
a homogeneous mixture is a mixture that is equal in all parts. a tossed salad may have some parts with more lettuce. a chocolate chip cookie might have more chocolate chips in one area. and chunky peanut butter is really chunky.
hope this helps<3
Answer:
The limiting reacting is O2
Explanation:
Step 1: data given
Number of moles O2 = 21 moles
Number of moles C6H6O = 4.0 moles
Step 2: The balanced equation
C6H6O + 7O2 → 6CO2 + 3H2O
Step 3: Calculate the limiting reactant
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
O2 is the limiting reactant. It will completely be consumed (21 moles).
C6H6O is in excess.
For 7 moles O2 we need 1 mol C6H6O
For 21 moles O2 we'll need 21/7 = 3 moles C6H6O
There will remain 4.0 - 3.0 = 1 mol C6H6O
Step 4: calculate products
For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O
For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2
For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O
The limiting reacting is O2