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Elodia [21]
3 years ago
12

Q2

Chemistry
1 answer:
sergey [27]3 years ago
5 0

Answer: 1.00 M

Explanation:

Moles of Solute/Liters of Solution = molarity. Then you would do 0.500 Moles/ 0.500 L and you get 1.00 M.

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A radioactive substance of mass 768g has a half life of 3 years. After how many years does it leave only 6g undecayed?​
vagabundo [1.1K]

Answer:

The answer is 21 years.

Explanation:

7×3

8 0
3 years ago
Read 2 more answers
Sarah measures out 151 grams of SO2. How many moles is this? Express your answer to three significant figures.
Anna11 [10]

Answer:

\boxed {\boxed {\sf 2.36 \ mol \ SO_2}}

Explanation:

We are asked to convert grams to moles. We will use the molar mass and dimensional analysis to perform this conversion.

<h3>1. Molar Mass</h3>

The molar mass is the mass of 1 mole of a substance. These values are found on the Periodic Table because they are equivalent to the atomic masses, but the units are grams per mole instead.

We are given a mass of sulfur dioxide (SO₂). Look up the molar masses of the individual elements.

  • Sulfur (S): 32.07 g/mol
  • Oxygen (O): 15.999 g/mol

Notice that the formula of the compound contains a subscript. The subscript after O means there are 2 moles of oxygen in 1 mole of sulfur dioxide. We must multiply oxygen's molar mass before adding sulfur's.

  • O₂: 15.999 * 2 = 31.998 g/mol
  • SO₂= 32.07 + 31.998 = 64.068 g/mol

<h3>2. Convert Grams to Moles </h3>

Now we will use dimensional analysis to convert grams to moles. From the molar mass, we know there are 64.068 grams of sulfur dioxide per mole, so we can set up a ratio.

\frac {64.068 \ g \ SO_2} {1 \ mol \ SO_2}

We are converting 151 grams to moles, so we multiply by this value.

151 \ g \ SO_2 *\frac {64.068 \ g \ SO_2} {1 \ mol \ SO_2}

Flip the ratio so the units of grams of sulfur dioxide cancel.

151 \ g \ SO_2 *\frac {1 \ mol \ SO_2}{64.068 \ g \ SO_2}

151  *\frac {1 \ mol \ SO_2}{64.068 }

\frac {151}{64.068 } \ mol \ SO_2

2.356870825 \ mol \ SO_2

<h3>3. Round </h3>

The original measurement of grams (151) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 6 in the thousandth place tells us to round the 5 in the hundredth up to a 6.

2.36 \ mol \ SO_2

151 grams of sulfur dioxide is approximately <u>2.36 moles of sulfur dioxide.</u>

8 0
3 years ago
For the reaction 2NH3(g)↽−−⇀3H2(g)+N2(g) 2 NH 3 ( g ) ↽ − − ⇀ 3 H 2 ( g ) + N 2 ( g ) the equilibrium concentrations were found
forsale [732]

Answer:

0.324

Explanation:

The following data were obtained from the question:

Concentration of NH3, [NH3] = 0.25 M

Concentration of H2, [H2] = 0.3 M

Concentration of N2, [N2] = 0.75 M

Equilibrium constant (Kc) =.?

The balanced equation for the reaction is given below:

2NH3 <==> 3H2 + N2

The equilibrium constant, Kc for a given reaction is the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient. Thus, the equilibrium constant for the above reaction can be obtained as illustrated below:

Kc = [H2]³ [N2] / [NH3]²

Concentration of NH3, [NH3] = 0.25 M

Concentration of H2, [H2] = 0.3 M

Concentration of N2, [N2] = 0.75 M

Equilibrium constant (Kc) =.?

Kc = [H2]³ [N2] / [NH3]²

Kc = [0.3]³ × [0.75] / [0.25]²

Kc = (0.027 × 0.75) / 0.0625

Kc = 0.02025 / 0.0625

Kc = 0.324

Therefore, the equilibrium constant for the reaction is 0.324

4 0
3 years ago
Which of these elements is an alkaline earth metal? potassium (k) calcium (ca) chromium (cr) gallium (ga)
Lunna [17]
Only calcium is an alkaline earth metal. 
6 0
3 years ago
Read 2 more answers
When zinc oxide reacts with dilute nitric acid, zinc nitrate is produced. The equation for the reaction is: ZnO + 2HNO₃→ Zn(NO₃)
Lisa [10]

ZnO + 2HNO₃→ Zn(NO₃)₂ + H₂O

mol Zn(NO₃)₂ = mol ZnO = 0.2 (from the coefficient)

mass Zn(NO₃)₂ = 0.2 x 189 = 37.8 g (theorethical yield)

% yield = 15.3 : 37.8 x 100% = 40.48%

6 0
2 years ago
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