1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vfiekz [6]
3 years ago
5

The space shuttle, in circular orbit around the Earth, collides with a small asteroid which ends up in the shuttle's storage bay

. For this collision,
a. neither momentum nor kinetic energy is conserved.
b. only momentum is conserved.
c. both momentum and kinetic energy are conserved.
d. only kinetic energy is conserved.
Physics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

b

Explanation:

The space shuttle, in circular orbit around the Earth, collides with a small asteroid which ends up in the shuttle's storage bay.

This form of collision is called inelastic collision. And inelastic collision momentum is conserved but the kinetic energy is not conserved. Hence the correct option is b. only momentum is conserved.

 

You might be interested in
What is a Serous circuit
PIT_PIT [208]

Answer:

Series circuit you mean : A series circuit is one with all the loads in a row. There is only ONE path for the electricity to flow. If this circuit was a string of light bulbs, and one blew out, the remaining bulbs would turn off.

Explanation:

4 0
3 years ago
Read 2 more answers
The flow of electrons in a circuit follows a path from the negative terminal of the battery to the positive terminal
SVEN [57.7K]

Answer:

No it's not true electric grow from Positive terminal to negative terminal

3 0
2 years ago
Carbon-14 is used to determine the time an organism was living. The amount of carbon-14 an organism has is constant with the atm
lutik1710 [3]

Answer:

The age of the organism is approximately 11460 years.

Explanation:

The amount of carbon-14 decays exponentially in time and is defined by the following equation:

\frac{n(t)}{n_{o}} = e^{-\frac{t}{\tau} } (1)

Where:

n_{o} - Initial amount of carbon-14.

n(t) - Current amount of carbon-14.

t - Time, measured in years.

\tau - Time constant, measured in years.

Then, we clear the time within the formula:

t = -\tau \cdot \ln \frac{n(t)}{n_{o}} (2)

In addition, time constant can be calculated by means of half-life of carbon-14 (t_{1/2}), measured in years:

\tau = \frac{t_{1/2}}{\ln 2}

If we know that \frac{n(t)}{n_{o}} = 0.25 and t_{1/2} = 5730\,yr, then the age of the organism is:

\tau = \frac{5730\,yr}{\ln 2}

\tau \approx 8266.643\,yr

t = -(8266.643\,yr)\cdot \ln 0.25

t \approx 11460.001\,yr

The age of the organism is approximately 11460 years.

8 0
3 years ago
Read 2 more answers
How many electrons have been removed from a positively charged electroscope if it has a net charge of 6x10-11?
faltersainse [42]

Answer:

<h3>Because one Coulomb of charge is an abnormally large quantity of charge, the units of microCoulombs (µC) or nanoCoulombs (nC) are more commonly used as the unit of measurement of charge. To illustrate the magnitude of 1 Coulomb, an object would need an excess of 6.25 x 1018 electrons to have a total charge of -1 C.</h3>

Explanation:

<h3><em><u>mark as brainliast</u></em></h3><h3><em><u>indian </u></em><em><u>genius </u></em><em><u>s</u></em><em><u>a</u></em><em><u>r</u></em><em><u>thak</u></em></h3>
4 0
3 years ago
Alan starts from his home and walks 1.3 km east to the library. He walks an additional 0.68 km east to a music store. From there
zepelin [54]

Answer: final Displacement = 0 km, total distance covered =7 km

Explanation:

Given the following :

From home to library = 1.3 km East

Library to music store = 0.68km East

Music store to friend's house = 1.1km North

Friend's house to grocery store = 0.42 km North

Displacement is the net change in distance traveled.

Eastward distance :

To = (1.3 + 0.68)km = 1.98km East

Fro = (0.68 + 1.3)km = 1.98 km East

Δ distance = (1.98 - 1.98) = 0

Northward direction:

To = (1.1 + 0.42)km = 1.52km north

Fro = (0.42 + 1.1)km = 1.52km North

Δ distance = (1.98 - 1.98) = 0

Hence final Displacement = 0

Total distance covered = 2 × (1.3 + 0.68 + 1.1 + 0.42) = 2 × 3.5

= 7km

3 0
3 years ago
Other questions:
  • an ideal gas system undergoes an adiabatic process in which it expands and does 20 J of work on its environment. how much energy
    14·1 answer
  • If a 10 kg object has 200 J of gravitational potential energy, how high was has it been lifted above the ground?
    9·1 answer
  • How does the movement of particles of matter change when matter goes from solid to liquid?
    10·1 answer
  • The soccer field is _____.
    13·2 answers
  • When an ice cube sits out on a warm day and melts where does the heat go?
    12·2 answers
  • A proton enters a magnetic field (B = 5.00 x 10^-2 T INTO THE PAGE) with
    13·1 answer
  • How is an image produced by a plane mirror different than an image produced by a convex mirror
    14·2 answers
  • What type of material does not transfer heat well
    12·2 answers
  • Map.
    7·1 answer
  • If someone has a special rank in brainly how do you feel
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!