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Leya [2.2K]
2 years ago
15

On which factor potential energy depends?​

Physics
2 answers:
Tom [10]2 years ago
7 0

\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}

\sf \red{what \: is \: potential \: energy}

\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}

Potential energy: A type of energy which is possessed by an object due its position.

Example: A raised weight or when we raise any weight is a potential energy.

\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}

\sf \red{on \: which \: factor \: potential \: energy \: depends}

\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}

Potential energy depends upon three factors. They are:

  1. Mass of an object.
  2. Height of an object.
  3. Gravitational force upon an object.

\boxed{ \huge \frak \red{brainlysamurai}}

Ludmilka [50]2 years ago
3 0

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂☘️

The potential energy of the object depends on

  • the height of the object with respect to some reference points,
  • the mass of the object,
  • the gravitational field the object is in.

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂☘️

Hope it helps ~

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In midair an M = 145 kg bomb explodes into two pieces of m1 = 115 kg and another, respectively. Before the explosion, the bomb w
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Answer:

v_2=-133.17m/s, the minus meaning west.

Explanation:

We know that linear momentum must be conserved, so it will be the same before (p_i) and after (p_f) the explosion. We will take the east direction as positive.

Before the explosion we have p_i=m_iv_i=Mv_i.

After the explosion we have pieces 1 and 2, so p_f=m_1v_1+m_2v_2.

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Since we know momentum must be conserved we have:

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So for our values we have:

v_2=\frac{(145kg)(24m/s)-(115kg)(65m/s)}{(145kg-115kg)}=-133.17m/s

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