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Leya [2.2K]
2 years ago
15

On which factor potential energy depends?​

Physics
2 answers:
Tom [10]2 years ago
7 0

\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}

\sf \red{what \: is \: potential \: energy}

\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}

Potential energy: A type of energy which is possessed by an object due its position.

Example: A raised weight or when we raise any weight is a potential energy.

\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}

\sf \red{on \: which \: factor \: potential \: energy \: depends}

\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}

Potential energy depends upon three factors. They are:

  1. Mass of an object.
  2. Height of an object.
  3. Gravitational force upon an object.

\boxed{ \huge \frak \red{brainlysamurai}}

Ludmilka [50]2 years ago
3 0

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂☘️

The potential energy of the object depends on

  • the height of the object with respect to some reference points,
  • the mass of the object,
  • the gravitational field the object is in.

▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂☘️

Hope it helps ~

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Answer:

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Explanation:

<u>Speed</u>

It's defined as the distance (d) per unit of time (t) traveled by an object. The formula is:

\displaystyle v=\frac{d}{t}

Let's call x the total distance covered by the train. It covered d1=1/3x with a speed of v1=25 km/h. The time taken is calculated solving for t:

\displaystyle t_1=\frac{d_1}{v_1}

\displaystyle t_1=\frac{1/3x}{25}

\displaystyle t_1=\frac{x}{75}

Now the rest of the distance:

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\displaystyle t_2=\frac{2x}{225}

The total time is:

\displaystyle t_t=\frac{x}{75}+\frac{2x}{225}

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\displaystyle t_t=\frac{5x}{225}

Simplifying:

\displaystyle t_t=\frac{x}{45}

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Simplifying:

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Suppose a gliding 2-kg cart bumps into, and sticks to, a stationary 5-kg cart. If the speed of the gliding cart before the colli
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Answer:

Therefore,

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v_{f}=4\ m/s

Explanation:

Given:

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Initial velocity of Glidding Cart = u₁ = 14 m/s

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To Find:

Final velocity of the coupled carts after the collision = v_{f}=?

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Therefore,

Final velocity of the coupled carts after the collision is

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