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Vesna [10]
4 years ago
12

I need to know more about science

Physics
1 answer:
Marizza181 [45]4 years ago
4 0

Answer:

The origin of science can be traced back to ancient Egypt and the Mesopotamia from about 3500 to 3000 BC. The achievements of these two civilizations in mathematics, astronomy, and medicine have reached and shaped the Greek natural philosophy in the classical era, and they usually formally try to explain events in the material world with natural causes . After the fall of the Western Roman Empire, in the first few centuries of the Middle Ages (approximately 400-1000 AD), knowledge about the ancient Greeks’ world concepts was gradually forgotten in Western Europe , while in the Muslim world of the Golden Age of Islam Was preserved in. From the 10th century to the 13th century, Western Europe retrieved the writings of ancient Greece and absorbed the research of Islamic scholars. Natural philosophy was revived, and then transformed in the scientific revolution that began in the 16th century The new ideas and discoveries during this period broke away from ancient Greek ideas and traditional methods. The rapid role of scientific method in acquiring knowledge, but the institutionalization and professionalization of science did not begin to take shape until the 19th century

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A hot air balloon is a sphere of volume 2210 m3. The density of the hot air inside is 1.13 kg/m3, while the air outside has a de
ch4aika [34]

Answer: Balloon is submerged in air, and when a body is submerged in a fluid, a buoancy force will act upward and equal to the weight of fluid displaced by the body.

Explanation:

8 0
3 years ago
If a ball of mass, M, moving at velocity, v, collided with a ball of mass 10M at rest, describe what could happen to the velocit
KatRina [158]
Refer to the diagram shown below.

Before collision, the momentum of the two masses is
P₁ = Mv + (10M)*0 = Mv

After the collision, assume that the lighter ball rebounds off the heavier ball with a coefficient of restitution of r, so that v₂ = rv.
If r = 1, the rebound is elastic and v₂ = -v.
If r < 1, the rebound velocity is v₂ = -rv.
If r= 0, the lighter ball sticks to the heavier ball.

The momentum after collision is
P₂ = -Mv₂ + 10Mv₁

Because momentum is conserved, P₁ = P₂. That is,
10Mv₁ - M(rv) = Mv
v₁ = v(1+r)/10  for r>0.

When r=1 (elastic rebound)
v₁ = v/5.
The heavier ball moves right at 20% of the velocity of the lighter ball,
and the lighter ball rebounds with its velocity in the opposite direction.

When 0 < r < 1,
v₁ = (1+r)/10.
The heavier ball travels with greater than 20% of the velocity of the lighter ball, and the lighter ball rebounds with a velocity less than its initial velocity.

When r=0, the balls will stick together and
(10M + M)v₁ = Mv
v₁ = v/11.
The stuck balls move together at 1/11 of the initial velocity of the lighter ball.


3 0
3 years ago
A resistance is added in parallel to a 470 Ω resistance to give an effective resistance of 330 Ω. What is the approximate value
saw5 [17]
I think its c on the test I had
4 0
4 years ago
A constant force of magnitude F acts on an object of mass 0.04kg initially at rest at a point O. If the speed of the object when
vampirchik [111]

Answer:

F = 100 Newtons

Explanation:

F = ?

m = 0.04kg

u = 0m/s ==> u is just an abbreviation for initial velocity, it is conventional.

s = 50m ==> s is just an abbreviation for distance, it is conventional.

v = 500m/s ==> v is just an abbreviation for final velocity, it is conventional.

v^{2} = u^{2} + 2as\\\\=> a = \frac{v^{2} - u^{2}}{2s}\\a = \frac{500^{2} }{2*50}\\a = 2500ms^{-2}

Then F = ma = 0.04 x 2500 = 100N

5 0
3 years ago
Estimate the average power output of the sun, given that about 1350 w/m2 reaches the upper atmosphere of the earth.
fenix001 [56]

the <u>average powe</u><u>r</u> output of the sun is <u>3.8 × </u>10^{26}<u> W</u> given that about 1350 w/m2 reaches the upper atmosphere of the earth.

As we know intensity falling over a surface is equal to Energy falling per unit area per unit volume.

I = \frac{Energy}{area*time}

Since Power is equal to energy/time

I = power/area

or

Power = Intensity × area

Now, Distance from Sun to Earth , r = 149.6 ×10^{9}  m

So, Surface area of the sphere of radius is:

A = 4 π r^{2}

= 4 × 3.14 × (149.6 × 10^{9})²

=  2.81 × 10^{23}m²

Thus Average Power output of the sun will be:

P = 1350 × 2.81 × 10^{23}

= 3.7935 × 10^{26}

P = 3.8 ×    10^{26}  W

So the average power output of the sun is 3.8 × 10^{26} W.

If you need to learn more about about the average power of a resistor, click here.

brainly.com/question/12972958

#SPJ4

7 0
2 years ago
Read 2 more answers
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