Answer:
if one bulb burns out, the other bulbs in the fixture continue to operate. Other uses include an electronic OR gate, where two switches are in a parallel circuit: one of the switches must be closed for the circuit to function.
<u>Answer:</u>
Strontium atom loses 2 electrons to become an ion.
<u>Explanation:</u>
Strontium (an Alkaline Earth metal) is the 38th element found in the Group 2 of the periodic table.
A Strontium atom has same number of electrons as its protons. It has a +2 electronegativity because it belongs to group 2 of the periodic table so it has the tendency to lose 2 electrons to form a positive ion.
Therefor, Strontium atom loses 2 electrons to become an ion with 2 electrons lesser than its atom.
Binding of a signaling molecule to ligand-gated ion channel leads directly to a change in the distribution of ions on opposite sides of the membrane
<u>Explanation:</u>
The ligand-gated-ion-channel is trans membrane protein buildings that conduction course through the channel pores in light of the official of a neurotransmitter. They are not quite the same as voltage - gated - ion - channels, which are delicate to film possibilities, and G-protein coupled receptors (GPCR's), which utilize second messengers.
These ion channels, additionally ordinarily referred to as ionotropic receptors, are a gathering of trans membrane -ion-channel proteins which open to permit ions, for example, 
and potentially 
to go through the layer in light of the official of a synthetic errand person, for example, a neurotransmitter.
The answer is Crest in transverse waves, this is where the particles are closest to each other due to the compression of the longitudinal component of the wave.
Answer:
1.265 Pounds
Explanation:
Data provided:
Tire outside diameter = 49"
Rim diameter = 22"
Tire width = 19"
Now,
1" = 0.0254 m
thus,
Tire outside radius, r₁ = 49"/2 = 24.5" = 24.5 × 0.0254 = 0.6223 m
Rim radius, r₂ = 22" / 2 = 11" = 0.2794 m
Tire width, d = 19" = 0.4826 m
Now,
Volume of the tire = π ( r₁² - r₂² ) × d
on substituting the values, we get
Volume of air in the tire = π ( 0.6223² - 0.2794² ) × 0.4826 = 0.46877 m³
Also,
Density of air = 1.225 kg/m³
thus,
weight of the air in the tire = Density of air × Volume air in the tire
or
weight of the air in the tire = 1.225 × 0.46877 = 0.5742 kg
also,
1 kg = 2.204 pounds
Hence,
0.5742 kg = 0.5742 × 2.204 = 1.265 Pounds
