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4 years ago

What is the concentration of each ion in 0.250 M Na2SO4?

Chemistry

1 answer:

kenny6666 [7]4 years ago

3 0

Answer: The concentration of $Na^+$ is 0.500 M and $SO_4^{2-}$ is 0.250 M in 0.250 M $Na_2SO_4$

Explanation:

The dissociation of $Na_2SO_4$ is given as:

$Na_2SO_4\rightarrow 2Na^++SO_4^{2-}$

As 1 mole of $Na_2SO_4$ gives = 2 moles of $Na^+$

0.250 moles of $Na_2SO_4$ gives = $\frac{2}{1}\times 0.250=0.500$ moles of $Na^+$

As 1 mole of $Na_2SO_4$ gives = 1 mole of $SO_4^{2-}$

0.250 moles of $Na_2SO_4$ gives = $\frac{1}{1}\times 0.250=0.250$ moles of $SO_4^{2-}$

Thus the concentration of $Na^+$ is 0.500 M and $SO_4^{2-}$ is 0.250 M in 0.250 M $Na_2SO_4$

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Answer:

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3 years ago

___________ minerals are dark-colored because they contain _____________. a. Mafic; iron and/or magnesium b. Felsic; iron and/or

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Answer:

A. Mafic; iron and/or magnesium

Explanation:

Let's find the answer by naming some minerals and their chemistry.

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Read 2 more answers

Determine the concentrations of MgCl2, Mg2+, and Cl− in a solution prepared by dissolving 2.52 × 10−4 g MgCl2 in 2.00 L of water

dybincka [34]

Answer:

Explanation:

Given parameters:

Mass of MgCl₂ = 2.52 x 10⁻⁴g

Volume of water = 2L

Unkown:

Concentration of MgCl₂ =?

Concentration of Mg²⁺ = ?

Concentration of Cl⁻ =?

Solution:

Concentration is defined as the number of moles of a solute contained in a solution.

Concentration = $\frac{number of moles }{volume}$

To find the number of moles"

number of moles = $\frac{mass}{molar mass}$

Molar mass of MgCl₂ = 24.3 + (2 x 35.5) = 95.3g/mol

number of moles = $\frac{0.000}{molar mass}$ = 0.000252moles

Concentration of MgCl₂ = $\frac{0.000252}{95.3}$ = 2.64 x 10⁻⁶moldm⁻³

from the formula of the compound;

1 mole of MgCl₂ contains 1 mole of Mg²⁺

Therefore, 2.64 x 10⁻⁶moldm⁻³ of MgCl₂ will contains 2.64 x 10⁻⁶moldm⁻³ of Mg

Also;

1 mole of MgCl₂ contains 2 mole of Cl⁻

2.64 x 10⁻⁶moldm⁻³ contains 2 x 2.64 x 10⁻⁶moldm⁻³; 5.29 x 10⁻⁶moldm⁻³

Expressing in ppm;

1ppm = 1mg/L

2.64 x 10⁻⁶moldm⁻³ to mg/L for Mg²⁺

2.64 x 10⁻⁶moldm⁻³ = 2.64 x 10⁻⁶moldm⁻³ x molar mass(g/mol)

= 2.64 x 10⁻⁶moldm⁻³ x 24.3 = 6.43 x 10⁻⁵g/L

g/L to mg/L; 6.43 x 10⁻⁵g/L x 1000 = 6.43 x 10⁻²mg/L = 6.43 x 10⁻²ppm

5.29 x 10⁻⁶moldm⁻³ to mg/L for Cl⁻;

5.29 x 10⁻⁶moldm⁻³ = 5.29 x 10⁻⁶moldm⁻³ x 35.5 = 1.88 x 10⁻⁴g/L

g/L to mg/L; 1.88 x 10⁻⁴g/L x 1000 = 1.88 x 10⁻¹mg/L = 1.88 x 10⁻¹ppm

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3 years ago