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SCORPION-xisa [38]
3 years ago
7

A sealed beaker of what you are told is aqueous nickel sulfide was given to you by the local chemist and you put it on the windo

w sill. after a few days, you notice that the mixture is getting thick toward the bottom. what is the nature of the initial nickel sulfide mixture, assuming that the temperature on the sill remained approximately constant?
Chemistry
2 answers:
Contact [7]3 years ago
8 0
Answer is: the nature of the initial nickel sulfide mixture is a suspension.
Suspension<span> is a </span>heterogeneous mixture (solute<span> particles do not </span>dissolve), <span>that contains </span>solid<span> particles (in this example nickel sulfide or NiS) sufficiently large for </span>sedimentation. <span> The internal phase (solid nickel sulfide) is dispersed throughout the external phase (water).</span>

rjkz [21]3 years ago
6 0

The nature of the initial nickel sulfide mixture : <u>suspension</u>

<h3>Further explanation </h3>

A pure substance can be an element or compound.

The element is a single substance that cannot be broken down anymore or the simplest substance.

While the compound is a pure substance that is formed from a combination of two or more elements through chemical reactions and has a constant chemical ratio.

A mixture is a combination of two or more single substances. The properties of the mixture component are not lost / unchanged as in compounds.

The mixture can be divided into a homogeneous mixture if the composition/ratio of each substance in the mixture is the same and heterogeneous mixture if the ratio of the composition of the substances is not the same (can be varied) in each place.

Mixtures can also be divided into solutions, suspensions, and colloids based mainly on the size of the particles

Homogeneous mixture = Solution

Heterogeneous mixture = suspension, and

The mixture is located between suspension and solution = Colloid

The solution is a mixture of two or more substances consisting of a solute and a solvent. The particle size of the solution is very small, less than 1 nm, it cannot be distinguished between the solute and its solvent medium. Substances in a solution cannot be separated through filtering.

The solution has the same composition in each of its parts.

Suspensions are rough mixes and are heterogeneous. Particle size more than 100 nm.

The mixture is a murky solution, but it gradually separates due to the influence of gravity (undergoes precipitation). Suspension can be separated by filtering.

Colloids are mixtures of dispersed particles and dispersing particles. The size of colloidal particles lies between 1 nm - 100 nm

colloid mixtures cannot be separated through ordinary filtering, but rather with ultrafilters.

Aqueous nickel sulfide (NiS) has been deposited after being placed several days, so it can be classified into a mixture of suspensions

<h3>Learn more </h3>

A heterogeneous mixture

brainly.com/question/5428813

a homogeneous mixture

brainly.com/question/1799869

an example of a physical change

brainly.com/question/1119909

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Na+ and Cl- __________ ___________________________ Na+ and PO4 3- __________ ___________________________ Na+ and SO4 2- ________
bagirrra123 [75]

Answer:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

(1) Sodium is carrying +1 charge called as Na^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral NaCl.

(2) Sodium is carrying +1 charge called as Na^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_3PO_4.

(3) Sodium is carrying +1 charge called as Na^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_2SO_4.

(4) Sodium is carrying +1 charge called as Na^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_2CO_3.

(5) Potassium is carrying +1 charge called as K^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form KCl.

(6) Potassium is carrying +1 charge called as K^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form K_3PO_4.

(7) Potassium is carrying +1 charge called as K^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form K_2SO_4.

(8) Potassium is carrying +1 charge called as K^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form K_2CO_3.

(9) Calcium is carrying +2 charge called as Ca^{+2} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form CaCl_2.

(10) Calcium is carrying +2 charge called as Ca^{+2} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form Ca_3(PO_4)_2.

(11) Calcium is carrying +2 charge called as Ca^{+2} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form CaSO_4.

(12) Calcium is carrying +2 charge called as Ca^{+2} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form CaCO_3.

(13) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form NH_4Cl.

(14) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form NH_4_3PO_4.

(15) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form NH_4_2SO_4.

(16) Ammonium ion is carrying +1 charge called as NH_4^{+1} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form NH_4_2CO_3.

(17) Iron is carrying +3 charge called as Fe^{+3} cation and chloride Cl^{-1} is an anion carrying -1 charge. They form FeCl_3.

(18) Iron is carrying +3 charge called as Fe^{+3} cation and phosphate PO_4^{-3} is an anion carrying -3 charge. They form FePO_4.

(19) Iron is carrying +3 charge called as Fe^{+3} cation and sulfate SO_4^{-2} is an anion carrying -2 charge. They form Fe_2(SO_4)_3.

(20) Iron is carrying +3 charge called as Fe^{+3} cation and carbonate CO_3^{-2} is an anion carrying -2 charge. They form Fe_2(CO_3)_3.

7 0
3 years ago
A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20
notsponge [240]

P1 * V1 ÷ T1 = P2 * V2 ÷ T2  

45 * 1.20 ÷ 314 = 96 * V2 ÷ 420  

30,144 * V2 = 22,680  

V2 = 22,680 ÷ 30,144  

The new volume is approximately 0.75 liter.

I hope I helped

5 0
3 years ago
Read 2 more answers
Enter ionic and net equations: feso4(aq)+ na3po4(aq) arrow fe3(po4)2(s)+na2so4(aq)
stepan [7]

Answer:

<em> ionic equation : </em>3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

<em> net ionic equation: </em>3Fe(2+)(aq)  + 2PO4 (3-)(aq) → Fe3(PO4)2(s)

Explanation:

The balanced equation is

3FeSO4(aq)+ 2Na3PO4(aq) → Fe3(PO4)2(s)+ 3Na2SO4(aq)

<em>Ionic equations: </em>Start with a balanced molecular equation.  Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions . Indicate the correct formula and charge of each ion. Indicate the correct number of each ion . Write (aq) after each ion .Bring down all compounds with (s), (l), or (g) unchanged. The coefficents are given by the number of moles in the original equation

3Fe(2+)(aq) + 3SO4(2-)(aq)+ 6Na(+)(aq) + 2PO4 (3-) (aq) → Fe3(PO4)2(s)+ 6Na(+) + 3SO4(2-)(aq)

<em>Net ionic equations: </em>Write the balanced molecular equation.  Write the balanced complete ionic equation.  Cross out the spectator ions, it means the repeated ions that are present.  Write the "leftovers" as the net ionic equation.

3Fe(2+)(aq)  + 2PO4 (3-)(aq) → Fe3(PO4)2(s)

6 0
3 years ago
What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.
koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

  • 1.000 mol salt is equal to 58.44 g salt
  • 1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

  • 1 L = 1dm³
  • 1 m³ = 10³ dm³

We can use proportions:

10.0m^{3} .\frac{10^{3}dm^{3}  }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt

8 0
3 years ago
Each of the following names is wrong. Draw structures based on them, and correct the names:(b) 1,1,1-trimethylheptane
devlian [24]

The correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

<h3>IUPAC NAME:</h3>

It is systematic way of nomenclature of organic compounds.

It is based on the position of functional groups, preference of the functional group, long or short chain of carbon, preference of double bond, single and triple bond, branching of carbon chain, etc.

The given compound is 1,1,1-trimethylheptane.

The given name is wrong according to IUPAC name because the numbering of carbon atom should be done in that way in which the carbon atom chain is largest.

Here, in this case the numbering is done from right side. Thus the largest carbon chain have 8 carbon atom.

If the numbering is done according to the question, number of carbon atom in straight chain is 7.

Thus, we concluded that the Correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

learn more about Nomenclature:

brainly.com/question/14094007

#SPJ4

5 0
2 years ago
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