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SCORPION-xisa [38]
3 years ago
7

A sealed beaker of what you are told is aqueous nickel sulfide was given to you by the local chemist and you put it on the windo

w sill. after a few days, you notice that the mixture is getting thick toward the bottom. what is the nature of the initial nickel sulfide mixture, assuming that the temperature on the sill remained approximately constant?
Chemistry
2 answers:
Contact [7]3 years ago
8 0
Answer is: the nature of the initial nickel sulfide mixture is a suspension.
Suspension<span> is a </span>heterogeneous mixture (solute<span> particles do not </span>dissolve), <span>that contains </span>solid<span> particles (in this example nickel sulfide or NiS) sufficiently large for </span>sedimentation. <span> The internal phase (solid nickel sulfide) is dispersed throughout the external phase (water).</span>

rjkz [21]3 years ago
6 0

The nature of the initial nickel sulfide mixture : <u>suspension</u>

<h3>Further explanation </h3>

A pure substance can be an element or compound.

The element is a single substance that cannot be broken down anymore or the simplest substance.

While the compound is a pure substance that is formed from a combination of two or more elements through chemical reactions and has a constant chemical ratio.

A mixture is a combination of two or more single substances. The properties of the mixture component are not lost / unchanged as in compounds.

The mixture can be divided into a homogeneous mixture if the composition/ratio of each substance in the mixture is the same and heterogeneous mixture if the ratio of the composition of the substances is not the same (can be varied) in each place.

Mixtures can also be divided into solutions, suspensions, and colloids based mainly on the size of the particles

Homogeneous mixture = Solution

Heterogeneous mixture = suspension, and

The mixture is located between suspension and solution = Colloid

The solution is a mixture of two or more substances consisting of a solute and a solvent. The particle size of the solution is very small, less than 1 nm, it cannot be distinguished between the solute and its solvent medium. Substances in a solution cannot be separated through filtering.

The solution has the same composition in each of its parts.

Suspensions are rough mixes and are heterogeneous. Particle size more than 100 nm.

The mixture is a murky solution, but it gradually separates due to the influence of gravity (undergoes precipitation). Suspension can be separated by filtering.

Colloids are mixtures of dispersed particles and dispersing particles. The size of colloidal particles lies between 1 nm - 100 nm

colloid mixtures cannot be separated through ordinary filtering, but rather with ultrafilters.

Aqueous nickel sulfide (NiS) has been deposited after being placed several days, so it can be classified into a mixture of suspensions

<h3>Learn more </h3>

A heterogeneous mixture

brainly.com/question/5428813

a homogeneous mixture

brainly.com/question/1799869

an example of a physical change

brainly.com/question/1119909

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kiruha [24]
I believe the correct answer from the choices listed above is option B. When equal masses of each are added to water, ethylene glycol would be more effective. Ethylene glycol is the most widely used automotive cooling-systemantifreeze, although methanol, ethanol, isopropyl alcohol, and propylene glycol are also used.
Hope this answers the question. Have a nice day.
6 0
3 years ago
Read 2 more answers
What is the pH of a 0.1 M phosphate buffer (pKa = 6.86) that contains equal amounts of acid and conjugate base?
Anvisha [2.4K]

Answer : The pH of a 0.1 M phosphate buffer is, 6.86

Explanation : Given,

pK_a=6.86

Concentration of acid = 0.1 M

Concentration of conjugate base (salt) = 0.1 M

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=6.86+\log (\frac{0.1}{0.1})

pH=6.86

Therefore, the pH of a 0.1 M phosphate buffer is, 6.86

4 0
3 years ago
Label the diagram below chapter 2
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Is there suppose to be a diagram attached to this?
3 0
2 years ago
What ratio of nitrogen and hydrogen molecules would result in no left-over reactants? Explain your answer.
madam [21]

A ration, Nitrogen to Hydrogen, of 1 : 3 would result in no left-over reactants

Explanation:

This is because Nitrogen and Hydrogen would react to form ammonia as shown in the following reaction below;

N₂ (g) + 3H₂ (g) → 2NH₃ (g)

For every mole of Nitrogen gas, you would require 3 moles of Hydrogen gas. This way they would react to form Ammonia with no leftover reactants.

Learn More:

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6 0
2 years ago
What is the percent yield of a reaction in which 51.5 g of tungsten(VI) oxide (WO3) reacts with excess hydrogen gas to produce m
Rus_ich [418]

Answer:

The percent yield of a reaction is 48.05%.

Explanation:

WO_3+3H_2\rightarrow W+3H_2O

Volume of water obtained from the reaction , V= 5.76 mL

Mass of water = m = Experimental yield of water

Density of water = d = 1.00 g/mL

M=d\times V = 1.00 g/mL\times 5.76 mL=5.76 g

Theoretical yield of water : T

Moles of tungsten(VI) oxide = \frac{51.5 g}{232 g/mol}=0.2220 mol

According to recation 1 mole of tungsten(VI) oxide gives 3 moles of water, then 0.2220 moles of tungsten(VI) oxide will give:

\frac{3}{1}\times 0.2220 mol=0.6660 mol

Mass of 0.6660 moles of water:

0.666 mol × 18 g/mol = 11.988 g

Theoretical yield of water : T = 11.988 g

To calculate the percentage yield of reaction , we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{m}{T}\times 100=\frac{5.76 g}{11.988 g}\times 100=48.05\%

The percent yield of a reaction is 48.05%.

7 0
3 years ago
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