Question

A helium filled balloon has a volume of 2.48L and a pressure of 150kpa the volume of the balloon increases to 2.98L what is the new pressure of the helium gas

Answer 1

Answer:

THE NEW PRESSURE OF THE HELIUM GAS IS 124kPa AFTER THE VOLUME WAS INCREASED FROM 2.48 L TO 2.98 L

Explanation:

Using Boyle's law which states that at constant temperature, the pressure of a given gas is inversely proportional to the volume occupied by the gas.

Mathematically,

P1 V1 = P2 V2

P1 = 150 kPa = 150 * 10^3 Pa

V1 = 2.48 L

V2 = 2.98 L

P2 = ?

Rearranging the formula making P2 the subject of the equation, we obtain;

P2 = P1 V1 / V2

P2 = 150 * 10^3 * 2.48 / 2.98

P2 = 372 * 10 ^3 / 2.98

P2 = 124.83 * 10^3 Pa or 124.8kPa

In other words, the new pressure of the helium gas after its volume was increased from 2.48 L to 2.98 L is 124.8kPa.