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Makovka662 [10]
3 years ago
15

A helium filled balloon has a volume of 2.48L and a pressure of 150kpa the volume of the balloon increases to 2.98L what is the

new pressure of the helium gas
Chemistry
1 answer:
Natali [406]3 years ago
5 0

Answer:

THE NEW PRESSURE OF THE HELIUM GAS IS 124kPa AFTER THE VOLUME WAS INCREASED FROM 2.48 L TO 2.98 L

Explanation:

Using Boyle's law which states that at constant temperature, the pressure of a given gas is inversely proportional to the volume occupied by the gas.

Mathematically,

P1 V1 = P2 V2

P1 = 150 kPa = 150 * 10^3 Pa

V1 = 2.48 L

V2 = 2.98 L

P2 = ?

Rearranging the formula making P2 the subject of the equation, we obtain;

P2 = P1 V1 / V2

P2 = 150 * 10^3 * 2.48 / 2.98

P2 = 372 * 10 ^3 / 2.98

P2 = 124.83 * 10^3 Pa or 124.8kPa

In other words, the new pressure of the helium gas after its volume was increased from 2.48 L to 2.98 L is 124.8kPa.

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The required formula of hydrate is MgSO₃.6H₂O.

<h3>How do we calculate the formula of hydrate?</h3>

The number of moles of water per mole of anhydrous solid (x) will be computed by dividing the number of moles of water by the number of moles of anhydrous solid (x) to find the hydrate's formula.

Moles will be calculated as:
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So formula of hydrate is MgSO₃.6H₂O.

Hence required formula of hydrate compound is MgSO₃.6H₂O.

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A metal with one valence electron is highly reactive compared to those with more than one electron.

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An atom with one valence electron have just one electron in its valence shell.

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