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Gennadij [26K]
3 years ago
8

TRUE OR FALSE: Chromosomes are made up of proteins joined together like beads on a string.

Chemistry
2 answers:
sveta [45]3 years ago
6 0

Answer:

true

Explanation:

vivado [14]3 years ago
4 0

Answer:

true

Explanation:

:)

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the mass of one hydrogen atom is 1.67x10^-27 kg. A cylinder contains 3.01x10^23 hydrogen atoms. What is the mass of the hydrogen
VladimirAG [237]
Multiply 1.67x10^-27 by 3.01x10^23
5 0
3 years ago
A substance registers a temperature change from 20 to 40 to what incremental temperature change does this correspond
ss7ja [257]

<u>Given:</u>

Initial temperature, T1 = 20 C

Final temperature, T2 = 40 C

<u>To determine:</u>

The temperature change

<u>Explanation:</u>

Convert degree C to Kelvin

Temperature in Kelvin = degree C + 273

T1 = 20 + 273 = 293 K

T2 = 40 + 273 = 313 K

Incremental temperature change = T2 - T1 = 313-293 = 20 K

Ans: The temperature change in kelvin is 20 K

3 0
3 years ago
What is the smallest division on 4 balance
tankabanditka [31]

Answer:0.1g

Explanation:

4 0
3 years ago
Read 2 more answers
A 5g piece of aluminum foil (c=0.897) at 100°C is dropped into a 25g container of water (c=4.184) at 20°C. What is the final tem
jeyben [28]

Answer:

23.6°C

Explanation:

use delta h method

5 0
3 years ago
Calculate the molar solubility of CaF2 in a 0.25 m solution of NaF(aq).
Kipish [7]

Answer:

6.4 × 10^-10 M

Explanation:

The molar solubility of the ions in a compound can be calculated from the Ksp (solubility constant).

CaF2 will dissociate as follows:

CaF2 ⇌Ca2+ + 2F-

1 mole of Calcium ion (x)

2 moles of fluorine ion (2x)

NaF will also dissociate as follows:

NaF ⇌ Na+ + F-

Where Na+ = 0.25M

F- = 0.25M

The total concentration of fluoride ion in the solution is (2x + 0.25M), however, due to common ion effect i.e. 2x<0.25, 2x can be neglected. This means that concentration of fluoride ion will be 0.25M

Ksp = {Ca2+}{F-}^2

Ksp = {x}{0.25}^2

4.0 × 10^-11 = 0.25^2 × x

4.0 × 10^-11 = 0.0625x

x = 4.0 × 10^-11 ÷ 6.25 × 10^-2

x = 4/6.25 × 10^ (-11+2)

x = 0.64 × 10^-9

x = 6.4 × 10^-10

Therefore, the molar solubility of CaF2 in NaF solution is 6.4 × 10^-10M

8 0
3 years ago
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