I need help with homework

(01.07 но) An experiment was conducted to determine the density of a liquid. The table shows a partial record of the experiment

Anestetic [448]

Answer:

How do you find the density of a liquid experiment?

To measure the density of a liquid you do the same thing you would for a solid. Mass the fluid, find its volume, and divide mass by volume. To mass the fluid, weigh it in a container, pour it out, weigh the empty container, and subtract the mass of the empty container from the full container.

3 0

2 years ago

How many Liters are in 1.245 x 10 6mL?

Kamila [148]

1245 liters because you move the decimal place over to the right six times

4 0

3 years ago

Why is hydrogen ion generation essential for atp production during photosynthesis

nika2105 [10]

Answer:

It is involved in the conversion of ADP to ATP

Explanation:

Most enzymes in biological systems function by reversible uptake and release of hydrogen in redox processes. The enzyme that catalyses the conversion of ADP to ATP also works by hydrogen ion transfer. Hence H+ is required in photosynthesis for the conversion of ADP to ATP

3 0

3 years ago

Carbon is black, crystalline and hard. Oxygen alone is a gas. How does the substance that is formed when these two elements comb

Margarita [4]

Carbon oxides (monoxide, dioxide) are gases :)

5 0

3 years ago

Suppose a 250. mL flask is filled with 0.30 mol of N_2 and 0.70 mol of NO. The following reaction becomes possible:N_2(g) +O2 →

Inessa [10]

Answer:

0.4 M

Explanation:

Equilibrium occurs when the velocity of the formation of the products is equal to the velocity of the formation of the reactants. It can be described by the equilibrium constant, which is the multiplication of the concentration of the products elevated by their coefficients divided by the multiplication of the concentration of the reactants elevated by their coefficients. So, let's do an equilibrium chart for the reaction.

Because there's no O₂ in the beginning, the NO will decompose:

N₂(g) + O₂(g) ⇄ 2NO(g)

0.30 0 0.70 Initial

+x +x -2x Reacts (the stoichiometry is 1:1:2)

0.30+x x 0.70-2x Equilibrium

The equilibrium concentrations are the number of moles divided by the volume (0.250 L):

[N₂] = (0.30 + x)/0.250

[O₂] = x/0.25

[NO] = (0.70 - 2x)/0.250

K = [NO]²/([N₂]*[O₂])

K = $\frac{(\frac{0.70 -2x}{0.250})^2 }{\frac{0.30+x}{0.250}*\frac{x}{0.250} }$

7.70 = (0.70-2x)²/[(0.30+x)*x]

7.70 = (0.49 - 2.80x + 4x²)/(0.30x + x²)

4x² - 2.80x + 0.49 = 2.31x + 7.70x²

3.7x² + 5.11x - 0.49 = 0

Solving in a graphical calculator (or by Bhaskara's equation), x>0 and x<0.70

x = 0.09 mol

Thus,

[O₂] = 0.09/0.250 = 0.36 M ≅ 0.4 M

3 0

3 years ago