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PIT_PIT [208]
3 years ago
10

A 25 kg child is bouncing on a trampoline, which can be treated as an ideal spring with spring constant 2900 N/m. If the trampol

ine compresses to a maximum of 0.38 m during the bouncing, what is the maximum height that she reaches above the uncompressed surface of the trampoline? You may ignore friction.
Physics
1 answer:
White raven [17]3 years ago
5 0

Answer:

Explanation:

Energy store in the compressed trampoline = potential energy of at the maximum height ignoring friction

energy stored in the trampoline = \frac{1}{2} kx^{2} where k is spring constant and x is the distance compressed  = 0.5 × 2900 × 0.38² = 209.38 J

209.38 J = 25 × 9.8 × h

h maximum height attain = 209.38 J / ( 25 × 9.8) = 0.855 m

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What is the heat flux (W/m^2), due to radiation heat transfer, from a black body if the surface temperature is 1000C? The convec
12345 [234]

Answer:

55000 W/m²

Explanation:

Parameters given:

Surface temperature, T = 1000°C

Hear transfer coefficient, h = 55 W/m²C

Convection heat transfer coefficient is given as:

h = Heat flux/Temperature

Hence, Heat Flux, q, is given as:

q = h * T

q = 55 * 1000 = 55000 W/m²C

7 0
3 years ago
Read 2 more answers
Write the realtionship between the density of a liquid and its upthrust? clarify​
kipiarov [429]

Answer:

B = ρ g V_liquid

the thrust is proportional to the density of the liquid

Explanation:

The density of a liquid is defined as the relationship between the mass and the volume of the liquid

         ρ = m / V

The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid

        B = W_liquid

        B = m _liquid g

we substitute mass for density

        B = ρ g V_liquid

therefore we see that the thrust is proportional to the density of the liquid

8 0
2 years ago
What happens to parallel light rays that strike a concave lens?
torisob [31]

Answer:

They diverge on refraction

Explanation:

When parallel light rays strike a concave lens, they will diverge that is they spread out .

Concave lens is also known as diverging lens, which means that when parallel rays of light strike on it, the lens spreads out the light rays ( that is it diverges the rays of light) that are refracted through it.

At the middle  of concave lens is thinner.  

When light is passes through the lens they diverge it or spread out.

The concave lens causes light rays to bend away or diverge from its axis since the concave lens is a diverging lens.  

5 0
3 years ago
New seafloor material is formed at places in Earth’s crust where –
mr_godi [17]

Answer:

D, I think.

Explanation:

I had a quiz in Plate Tectonics and there was 2 questions that are related to this, but not the exact question.

Which material rises from cracks in oceanic crust

-molten rock

Which is the first step in the seafloor spreading process?

-a crack forms in oceanic crust.

those are all right btw, so you can decide if the answer I told you is right or not.

4 0
2 years ago
Read 2 more answers
Part A If the velocity of a pitched ball has a magnitude of 47.5 m/s and the batted ball's velocity is 51.5 m/s in the opposite
nalin [4]

Explanation:

Let us assume that the mass of a pitched ball is 0.145 kg.

Initial velocity of the pitched ball, u = 47.5 m/s

Final speed of the ball, v = -51.5 m/s (in opposite direction)

We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :

\Delta p=m(v-u)\\\\\Delta p=0.145\times ((-51.5)-47.5)\\\\\Delta p=-14.355\ kg-m/s

So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.

Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :

J=\dfrac{\Delta p}{t}\\\\J=\dfrac{14.355}{2\times 10^{-3}}\\\\J=7177.5\ kg-m/s

Hence, this is the required solution.

7 0
3 years ago
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