Answer is 14.5 g L⁻¹.
<em>Explanation;</em>
Here, the question says reduce the units as one.
The presented units are g/L. To reduce the units to one, what we can do is take L to the upper side.
This can be done according to the rules of indices;
1 / aˣ = a⁻ˣ
Like that, we can write 1 / L as L⁻¹.
Hence, the reduced unit is g L⁻¹.
But remember to keep a space between when writing two different units.
Actually, this is an unit for density.
A food provides enough energy to raise the temperature of 2000 grams of water by 10°c contains 20 KCa.
1 Calorie is the amount of heat needed to elevate one gram of water to one degree Celsius temperature at one atmosphere of pressure.
The term "kilocalorie" is used to describe the amount of energy needed to increase 1 L of water's temperature by one degree Celsius at sea level.
Given
Mass of water (m) = 2000 g
Temp raise (ΔT) = 10°C
Heat capacity of water (C) = 1 calorie/g-C
Formula used
Heat (ΔH) = m × C × ΔT
= 2000 × 10 = 20000 C
In Kilo calories
20000 C = 20000/1000 = 20 KCa
Hence, a food provides enough energy to raise the temperature of 2000 grams of water by 10°c contains 20 KCa.
Learn more about Calories here brainly.com/question/23688200
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