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4 years ago

___is when a force is exerted on an object and the object moves a distance in the direction of the force.

Physics

2 answers:

Ilia_Sergeevich [38]4 years ago

8 0

That's a description of WORK in Physics.

defon4 years ago

5 0

The correct option is A) work.

Work is said to be done by a force when a force is exerted on an object and the the object on which the force is exerted moves in the direction of the force.

The amount of work done is given by the product of the force and the displacement made by the object.

Option (B) is incorrect, since Watt is the unit of power.

Option (C) is wrong, since joule is the unit of work or energy.

Option (D) is wrong, since power is the rate at which work is done.

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How many miles of MgCI2 are there in 339g of compound?

harkovskaia [24]

I'm going to answer this by using rounded numbers for the atomic masses. You need only go back and put the numbers in from your periodic table. My answers will be close, but not what you should get.

Find the Molar Mass of MgCl2

Mg = 24 grams

2Cl = 2 * 35.5 = 71 grams

Total = 95 grams

Find the mols in 339 grams

1 mole = 95 grams

x mol = 339

Solve

339 = 95x Divide by 95

339/95 = x

x = 3.67 mols Answer

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3 years ago

A student in the Biomechanics class has decided that she would like to make her arms

Rufina [12.5K]

Answer:

what is heat and transfer

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3 years ago

How much power is needed to move a 2000 kg mass from the bottom of the 150 m talk great pyramid in Egypt up a ramp if the ramp h

docker41 [41]

Answer:

How Heavy? More than 2,300,000 limestone and granite blocks were pushed, pulled, and dragged into place on the Great Pyramid. The average weight of a block is about 2.3 metric tons (2.5 tons).

Explanation:

4 0

3 years ago

In the mobile m1=0.42 kg and m2=0.47 kg. What must the unknown distance to the nearest tenth of a cm be if the masses are to be

LuckyWell [14K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From he question we are told that

The first mass is $m_1 = 0.42kg$

The second mass is $m_2 = 0.47kg$

From the question we can see that at equilibrium the moment about the point where the string holding the bar (where $m_1 \ and \ m_2$ are hanged ) is attached is zero

Therefore we can say that

$m_1 * 15cm = m_2 * xcm$

Making x the subject of the formula

$x = \frac{m_1 * 15}{m_2}$

$= \frac{0.42 * 15}{0.47}$

$x = 13.4 cm$

Looking at the diagram we can see that the tension T on the string holding the bar where $m_1 \ and \ m_2$ are hanged is as a result of the masses ( $m_1 + m_2$ )

Also at equilibrium the moment about the point where the string holding the bar (where ( $m_1 +m_2$ ) and $m_3$ are hanged ) is attached is zero

So basically

$(m_1 + m_2 ) * 20 = m_3 * 30$

$(0.42 + 0.47) * 20 = 30 * m_3$

Making $m_3$ subject

$m_3 = \frac{(0.42 + 0.47) * 20 }{30 }$

$m_3 = 0.59 kg$

3 0

3 years ago

A baseball with a mass of 151 g is thrown horizontally with a speed of 39.5 m/s (88 mi/h) at a bat. The ball is in contact with

Oduvanchick [21]

Answer:

the average force exerted on the ball by the bat is 11,613.27 N

Explanation:

Given;

mass of the baseball, m = 151 g = 0.151 kg

initial velocity of the baseball, u = 39.5 m/s

final velocity of the baseball, v = 45.1 m/s

time of action, t = 1.10 ms = 1.10 x 10⁻³ s

The average force exerted on the ball by the bat is calculate as;

$F = ma = \frac{m(v-u)}{t} \\\\F = \frac{0.151(45.1-(-39.5))}{1.10\times 10^{-3}} \\\\F = \frac{0.151(45.1\ +\ 39.5)}{1.10\times 10^{-3}} \\\\F = 11,613.27 \ N$

Therefore, the average force exerted on the ball by the bat is 11,613.27 N

7 0

2 years ago