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3 years ago

___is when a force is exerted on an object and the object moves a distance in the direction of the force.

Physics

2 answers:

Ilia_Sergeevich [38]3 years ago

8 0

That's a description of WORK in Physics.

defon3 years ago

5 0

The correct option is A) work.

Work is said to be done by a force when a force is exerted on an object and the the object on which the force is exerted moves in the direction of the force.

The amount of work done is given by the product of the force and the displacement made by the object.

Option (B) is incorrect, since Watt is the unit of power.

Option (C) is wrong, since joule is the unit of work or energy.

Option (D) is wrong, since power is the rate at which work is done.

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A polar bear runs at a speed of 11 m/s and has a mass of 380.2 kg. How much Kinetic energy does the bear have?

Yanka [14]

Answer:

$\boxed{\sf Kinetic \ energy \ of \ the \ bear (KE) = 23002.1 \ J}$

Given:

Mass of the polar bear (m) = 6.8 kg

Speed of the polar bear (v) = 5.0 m/s

To Find:

Kinetic energy of the polar bear (KE)

Explanation:

Formula:

$\boxed{ \bold{\sf KE = \frac{1}{2} m {v}^{2} }}$

Substituting values of m & v in the equation:

$\sf \implies KE = \frac{1}{2} \times 380.2 \times {11}^{2}$

$\sf \implies KE = \frac{1}{ \cancel{2}} \times \cancel{2} \times 190.1 \times 121$

$\sf \implies KE = 190.1 \times 121$

$\sf \implies KE = 23002.1 \: J$

$\therefore$

Kinetic energy of the polar bear (KE) = 23002.1 J

5 0

3 years ago

Matt and Anna Killian are frequent fliers on Fast-n-Go Airlines. They often fly between two cities that are a distance of 1575

marin [14]

Answer:

Speed of wind = 50mi/hr, Speed of plane in still air = 400mi/hr

Explanation:

Let the speed of the wind = Vw,

Speed of the plane in still air = Vsa,

The first trip the average speed of the plane = 1575mi/4.5hours = 350mi/hr

The coming trip the wind behind = 1575mi/3.5hrs = 450

Write the motion in equation form

First trip ( the plane flew into the wind)

Vaverage = Vsa - Vw

350 = Vsa - Vw

Second trip the wind was behind

450 = Vsa +Vw

Adding the two equation

800 = 2Vas

Vas = 800/2 = 400mi/hr

Substitute for Vas into equation 1

350mi/hr = 400mi/hr - Vw

Vw = 400-350 = 50mi/hr

6 0

2 years ago

The magnitude of the magnetic field at a certain distance from a long, straight conductor is represented by B. What is the magni

den301095 [7]

Answer:

Option C is correct.

The magnitude of the field is reduced to half at twice the distance,

Explanation:

The magnetic field produced in a long, straight conductor carrying a current I at distance r is given by

B = μ₀I/2πr

Where μ₀ is the constant permeability of free space.

If we increase the distance by twice then

B = μ₀I/2π(2r)

B = μ₀I/2πr(2)

B = B/2

Therefore, the magnitude of magnetic field is reduced by B/2 at twice the distance.

4 0

3 years ago

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Travka [436]

Answer:

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3 0

3 years ago

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What is the uses of echoes?<br>

vichka [17]

Explanation:

Echo sounding is a type of sonar used to determine the depth of water by transmitting sound waves into water. The time interval between emission and return of a pulse is recorded, which is used to determine the depth of water along with the speed of sound in water at the time.

8 0

3 years ago