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bagirrra123 [75]
4 years ago
8

___is when a force is exerted on an object and the object moves a distance in the direction of the force.

Physics
2 answers:
Ilia_Sergeevich [38]4 years ago
8 0
That's a description of WORK in Physics.
defon4 years ago
5 0

The correct option is A) work.

Work is said to be done by a force when a force is exerted on an object and the the object on which the force is exerted moves in the direction of the force.

The amount of work done is given by the product of the force and the displacement made by the object.

Option (B) is incorrect, since Watt is the unit of power.

Option (C) is wrong, since joule is the unit of work or energy.

Option (D) is wrong, since power is the rate at which work is done.

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What is a lunar month
Ira Lisetskai [31]

Answer:

It's the duration between successive new moons. Also called a lunation or synodic month, it has a mean period of 29.53059 days (29 days 12 hours and 44 minutes).

7 0
3 years ago
Read 2 more answers
A 40.0 kg block of lead is heated from -25°C to 200°C.
irga5000 [103]

Answer:

B. 1,170,000 J

Explanation:

Given;

mass of lead block, m = 40 kg

initial temperature, t₁ = -25 ⁰C

final temperature, t₂ = 200 ⁰C

The heat absorbed the lead block is calculated as;

H = mcΔt

where;

c is the specific heat capacity of lead =  130 J/kg⁰C

H = 40 x 130 x (200 - (-25))

H = 40 x 130 x (200 + 25)

H = 40 x 130 x 225

H = 1,170,000 J

Therefore, the heat absorbed the lead block is 1,170,000 J

4 0
3 years ago
Determine the kinetic energy of 650 kg roller coaster car that is moving with a speed of 20.0 miles per second?
mestny [16]

Answer:Ek=673.109 kJ

Explanation:

Use equation for Kinetic energy: Ek=m*V²/2

m=650 kg (mass of roller coaster)

V=20.0Miles/s=20.0*1.609m/s=32.18m/s

Ek=m*V²/2

Ek=650kg*(32.18m/s)²

Ek=(650kg*1053.55m²/s²)/2

Ek=673 108.8 J

Ek=673.109 kJ

4 0
3 years ago
Magnetic Field: is a region around the charged particle where the electric force is exerted on other charged particles.
nalin [4]
The answer for this question should be TRUE
8 0
2 years ago
Bob is pulling a 30kg filing cabinet with a force of 200N , but the filing cabinet refuses to move. The coefficient of static fr
vredina [299]

Answer:

2.0\cdot 10^2 N

Explanation:

The cabinet does not move: this means that the net force acting on it is zero.

Along the horizontal direction, we have two forces:

- The push exerted by Bob, F = 200 N, forward

- The frictional force, F_f, which acts in the opposite direction (backward)

Since the net force must be zero, we have:

F-F_f = 0

So solving the equation we can find the magnitude of the friction force:

F_f = F = 200 N=2.0 \cdot 10^2 N

7 0
4 years ago
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