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zysi [14]
3 years ago
12

The vertical height of an ocean wave from a crest to a trough is 10 meters. What is the amplitude of the ocean wave?

Physics
2 answers:
natima [27]3 years ago
6 0

The amplitude of the wave would be 5 meters.
Fed [463]3 years ago
5 0

Answer:

Amplitude, A = 5 m                    

Explanation:

It is given that, the vertical height of an ocean from a crest to trough is 10 meters.

The attached figure shows the vertical height from a crest to a trough is 10 m. We know that the maximum displacement of the wave is called its amplitude. A represents the amplitude of wave. It is the distance from the baseline to the crest or to the trough.

So, the amplitude of the ocean wave must be equal to half of wave's height i.e. 10/2 = 5 meters.

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You throw a rock straight up and find that it returns to your hand 3.40 s after it left your hand. Neglect air resistance. What
Soloha48 [4]

Answer:

The maximum height of the rock is 14.2 m

Explanation:

The equations that describe the height and velocity of the rock are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height of the object at time t

y0 = initial height

t = time

g = acceleration due to gravity (-9.8 m/s² if upward is positive)

v = velocity of the object at time t

We know that at t = 3.40 s, the rock is in your hand again. Then, if we place the origin of the frame of reference at your hand, the position of the rock at 3.40 s is 0 m. Using the equation of the position, we can calculate the initial velocity that we will need to obtain the max-height.

y = y0 + v0 · t + 1/2 · g · t²

0 = v0 · 3.40 s - 1/2 · 9.8 m/s² · (3.40 s)²

(1/2 · 9.8 m/s² · (3.40 s)² ) / 3.40 s = v0

v0 = 16.7 m/s

At max-height, the velocity of the rock is 0. Then, using the equation of velocity we can calculate the time it takes the rock to reach the max-height. With that time, we can calculate the maximum height.

v = v0 + g · t      (at max-height, v = 0)

0 = 16.7 m/s - 9.8 m/s² · t

- 16.7 m/s /  - 9.8 m/s² = t

t = 1.70 s

Now, using this time in the equation of height:

y = y0 + v0 · t + 1/2 · g · t²

y = 0 m + 16.7 m/s · 1.70 s - 1/2 · 9.8 m/s² · (1.70 s)²

y = 14.2 m

The maximum height of the rock is 14.2 m

8 0
3 years ago
What is the kinetic energy of a 2000 kilogram boat moving at 5m/sec?
Tanya [424]
<span>Hello!
KE=1/2MV^2 where M=2000 kg and V=5 m/s .5(2000)*(5^2)=25000 J</span>
4 0
3 years ago
Solubility Curve Practice Problems Worksheet 1
maxonik [38]
I don’t understand can you please explain your question thank u
6 0
3 years ago
A 0.350kg bead slides on a curved fritionless wire,
LuckyWell [14K]

Answer:

h2 = 0.092m

Explanation:

From a balance of energy from point A to point B, we get speed before the collision:

m1*g*h-\frac{m1*V_B^2}{2}=0  Solving for Vb:

V_B=\sqrt{2gh}=6.56658m/s

Since the collision is elastic, we now that velocity of bead 1 after the collision is given by:

V_{B'}=V_B*\frac{m1-m2}{m1+m2} = \sqrt{2gh}* \frac{m1-m2}{m1+m2}=-1.34316m/s

Now, by doing another balance of energy from the instant after the collision, to the point where bead 1 stops, we get the distance it rises:

m1*g*h2-\frac{m1*V_{B'}^2}{2}=0 Solving for h2:

h2 = 0.092m

6 0
3 years ago
PLEASE HELP ME A lens with a surface that curves outward like the exterior of a sphere is __________. (Points : 1) reflected ref
yanalaym [24]
Convex.

Concave curved inward (like how a cave foes in) and convex curves outward. Reflected and refracted do not apply to a lens.
3 0
3 years ago
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