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Dahasolnce [82]
3 years ago
6

What was the initial temperature of a gas contained in a 2.0-L bottle at a pressure of 1.00 atm if it was placed under vacuum an

d its pressure was reduced to 0.82 at mat a temperature of 10.0º C? Assume pressure remains constant
Chemistry
1 answer:
lesya692 [45]3 years ago
4 0
V1/T1 = V2/T2 

Substitute the value use ratio and proportion. Use calculator. 

V1 = (V2 x T1) / T2

1 is initial, 2 is final
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Bad White [126]

The balanced chemical reaction is :

O_2 + 4Na \ -> \ 2Na_2O

Number of moles of Na, n = \dfrac{14.6}{23} = 0.635 \  mol .

Now, from balance chemical reaction we can see that 1 mole of oxygen reacts with 4 moles of sodium.

So, number of moles of oxygen are :

n = \dfrac{0.635}{4}\  mole

So, amount of oxygen required is :

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Therefore, 5.08 gram of oxygen will react with 14.6 gram of sodium.

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