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sergey [27]
3 years ago
9

One of the unsolved problems in Number Theory is whether there exist

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Answer:

True.

Step-by-step explanation:

Computers have been used to check odd numbers up to 10^300  and no odd perfect numbers exist in this range , but that is not a proof that they don't exist.

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What is the area of the parallelogram?
IgorC [24]

Complete Question

What is the area of the parallelogram?

Slant Height = 21 cm

Height = 15 cm

Base = 20 cm

Answer:

300cm²

Step-by-step explanation:

The formula for the area of the parallelogram = Base × Height

Base = 20cm

Height = 15cm

Area = Base × Height

= 20cm × 15cm

= 300 cm²

Therefore, the area of the parallelogram is 300 cm²

3 0
2 years ago
. Simplify an expression for the area of the rectangle shown above
mel-nik [20]
8x+3x5=66 there you go
3 0
2 years ago
The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula
Semmy [17]

Answer:

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

V=\frac{4}{3} \pi r^{3}

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

V=\frac{4}{3} \pi r^{3}   ......Given

3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

5 0
3 years ago
22. If triangle DEC equals about triangle BEC, which is true by CPCTC?
Kruka [31]
<span>D. Line AE equals about line ED because if you measure line AE it is the same length as line ED</span>
4 0
2 years ago
Read 2 more answers
HELP DUE IN 10 MINS!!
fredd [130]

Answer:

  • D. No, they are not similar.

Step-by-step explanation:

<u>Check the ratio of the two given sides:</u>

  • MV/VT = 21/49 = 3/7
  • LV/VU = 8/28 = 2/7

Ratios are different so the triangles are not similar

Correct choice is D

5 0
3 years ago
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