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3 years ago

One of the unsolved problems in Number Theory is whether there exist

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

3 0

Answer:

True.

Step-by-step explanation:

Computers have been used to check odd numbers up to 10^300 and no odd perfect numbers exist in this range , but that is not a proof that they don't exist.

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Please Help!!!!!!!!!

marissa [1.9K]

124 square units
you just have to count the top, bottom, and a side and times by 2

4 0

3 years ago

What is the solution to this equation x-16=-8

arsen [322]

X-16=-8
Add 16 on both sides
x=-8+16
And solve; your answer will be
x=8

3 0

3 years ago

Tim Worker expects Social Security benefits of $937 per month. His wife, Mary, is eligible for a wife's benefit of 50 percent of

serg [7]

Answer:

The answer is B: 468.50

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

Please help me figure this out it’s due on 15 minutes

Olin [163]

Answer:

Step-by-step explanation:

1. area of square=10²=100 cm²

area of circle=πr²=π×2.5²=6.25π cm²

reqd. area=100-6.25π ≈80.375 cm²

area of circle=π×2.5²=6.25π≈6.25×3.14≈19.625 cm²

area of rectangle=4×3=12 cm²

reqd. area=19.625-12≈7.625 cm²

area of two circles=2×π×3²=18π≈18×3.14≈56.52 cm²

area of square=12²=144 cm²

reqd. area=144-56.52≈87.48 cm²

area of smaller circle=π×4²=16π cm²

area of bigger circle=π×8²=64π cm²

area of two circles=16π+64π=80π cm²

diameter of bigger circle=4+4+8+8=24 cm

diameter of biggest circle=π×12²=144π

area of shaded region=144π-80π=64π≈200.96 cm²

5 0

3 years ago

Find sin(a+B)

diamong [38]

Answer:

Cos A=5/13

we have

Cos² A= $1-Sin ²A$

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A= $\sqrt{144/169}=12/13$

again

Tan B=4/3

P/b=4/3

p=4

b=3

h= $\sqrt{3²+4²}=5$

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

Sin(A+B):sinAcosB+CosAsinB

now 

substitute value

Sin(A+B):12/13*3/5+5/13*(-4/5)=36/65-4/13

=16/65 is a required answer

6 0

3 years ago