I just wrote it out so hope this helps :)
4y + 10 =
2(2y + 5) <== factored form
Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
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Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
B^2+b+1(b^2 - b+1)
b^2+b+1-b^2+b+1
(b^2 - b^2) - (b+b) +(1h1l
=26