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3 years ago

Ultraviolet waves are ________.

Physics

1 answer:

Vitek1552 [10]3 years ago

3 0

The answer to this would be C

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What do we call a solution that has as many ions as it can hold?

igomit [66]

A saturated solution

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5. Sarah is standing 32.0 m away from Jason. If Sarah throws a snowball at a 45 degree

padilas [110]

Answer:

Explanation:

If air resistance is ignored and assume UP and Toward Jason are the positive directions.

horizontal analysis

d = (vx₀)t

t = d/vx₀

horizontal analysis

0 = vy₀t + ½gt²

0 = vy₀(d/vx₀)+ ½g(d/vx₀)²

as vy₀ = v₀sin45 and vx₀ = v₀cos45 and are equal.

0 = d + ½g(d²/v₀²cos²45)

-d = ½g(d²/v₀²cos²45)

-dv₀² = ½g(d²/cos²45)

v₀² = -½g(d/cos²45)

v₀² = -½(-9.81(32.0/cos²45)

v₀² = 313.92

v₀ = 17.717787...

v₀ = 17.7 m/s

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3 years ago

HELPPP WILL GIVE BRAINLIEST!!!

lesantik [10]

Answer: C

Explanation: As the universe stretches it expands more and more the distance between each other. Hope this helps.

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3 years ago

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A particle with a charge of -4.0 μC and a mass of 3.2 x 10-6 kg is released from rest at point A and accelerates toward point B,

Assoli18 [71]

Answer:

$V_B-V_A=-20736-0=-20736volt$

Explanation:

We have given charge on the particle $q=-4\mu C=-4\times 10^{-6}C$

Mass of the charge particle $m=3.2\times 10^{-6}kg$

From energy of conservation kinetic energy will be equal to potential energy

So at point A

$\frac{1}{2}mv^2=qV$

At point a velocity is zero

So $\frac{1}{2}(3.2\times10^{-6} )0^2=-4\times 10^{-6}V_a$

$V_A=0volt$

At point B velocity will be 72 m/sec

So $\frac{1}{2}\times 3.2\times 10^{-6}72^2=-4\times 10^{-6}V_b$

$V_B=-20736volt$

So $V_B-V_A=-20736-0=-20736volt$

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3 years ago

Two particles of masses m and 3m are moving toward each other along the x-axis with the same speed v. They undergo a head- on el

astra-53 [7]

Answer:0

Explanation:

Given

two particles of mass m and 3m

They move towards each other with velocity v

As the collision is Elastic therefore value of coefficient of restitution is 1

$e=1$

$e=\frac{Relative\ speed\ after\ collision}{Relative\ speed\ before\ collision}$

if $u_1$ and $u_2$ are velocity of approach of m and 3 m

and $v_1$ and $v_2$ are velocity after collision respectively

therefore

$v_2-v-1=u_1-u_2$

$v_2-v_1=v-(-v)$

$v_2-v_1=2 v$

conserving momentum

$m\cdot v+3m\cdot (-v)=3m\cdot (v_2)+m\cdot v_1$

$-2mv=3mv_2+m(v_2-2v)$

$4mv_2=0$

$v_2=0$

Therefore velocity of heavier mass is zero

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3 years ago

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