Total of 127.013 C of charge is passed
Given
weight of Ag solution before current has passed = 1.7854 g
weight of Ag solution after current has passed = 1.8016 g
Molecular mass of Ag = 107.86 g
Faraday's Constant = 96485
First of all we have to apply Faraday's First Law of Electrolysis i.e
m = ZQ
where
Z is propotionality constant (g/C)
Q is charge (C)
Hence,
Z = Atomic mass of substance/ Faraday's Constant
= 
= 0.0011178 g/C
Now ,
change in mass before and after the passing of current (Δm)
Δm = 1.8016g-1.7854g
= 0.0162g
Now amount of coulombs passed = 
amount of coulombs passed = 127.03524 C
Thus from the above conclusion we can say that amount of coulombs have passed is 127.03524 C
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Answer:
Lithium and Sodium
Explanation:
Losing and electron in natural setting is characterizes of elements in group one. These are elements known as the alkaline earth metals. They are the most electropositive elements on the periodic table.
These elements ionize by losing an electron yin their outermost shell to attain the configuration of the nearest noble gas. These elements are usually found in combined and rarely seen in uncombined state principally due to their very reactive nature.
Sodium naturally would ionize by losing one electron. Other elements capable of this even at a better rate because they are more electropositive are potassium and lithium. Both are also group one alkaline metals