Answer:
tortoise distance w.r.t sloth is 28.08 m further
Explanation:
given data
average speed v1 = 0.037 m/s
walking speed v2 = 0.076 m/s
time t = 12 min = 720 seconds
to find out
how much tortoise have gone wrt sloth
solution
we find here first tortoise walk that is
distance d1 = v2 × t
distance d1 = 0.076 × 720
distance d1 = 54.72 m
and sloth walk distance
distance d2 = v1 × t
distance d2 = 0.037 × 720
distance d2 = 26.64 m
and so
tortoise distance w.r.t sloth = d1 - d2
tortoise distance w.r.t sloth = 54.72 - 26.64 = 28.08
tortoise distance w.r.t sloth is 28.08 m further
Answer:
The phase difference between these two waves is 141.1⁰
Explanation:
The displacement of the wave is given as;
Amplitude, A = 2yₓCos(¹/₂Φ)
Since the amplitude of the combination is 1.5 times that of one of the original amplitudes = yₓ = 1.5 × A = 1.5A
A = 2(1.5A)Cos(¹/₂Φ)
A = 3ACos(¹/₂Φ)
¹/₃ = Cos(¹/₂Φ)
(¹/₂Φ) = Cos ⁻(0.3333)
(¹/₂Φ) = 70.55°
Φ = 141.1°
The phase difference between these two waves is 141.1⁰
Average speed = total distance / total time
= (81 + 88) / (2 + 2)
= 169/4
= 42.25 kilometers/hour
Let me know if you have any questions.
I solved it and got 374.2N so i would put 375N
sorry i didn’t get any of the ones on there, i probably made a mistake.
