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2 years ago

How long have scientists been recording the strength of the Earth's magnetic field?

2 answers:

7 0

Since 1840 we have been accurately enough to tell how the magnetic feild works, every 300,000 years it flips that hasn't occurred for 800,000 years though, hope this helps.<span />

jenyasd209 [6]2 years ago

7 0

Explanation:

The strength of the magnetic field was first measured in 1835 by Carl Friedrich Gauss and has been measured numerous times since then, showing a relative decay of 10% in the last 150 years. Currently, satellites use magnetometers to probe the three-dimensional structure of the Earth's magnetic field.

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Three +3.0-μC point charges are at the three corners of a square of side 0.50 m. The last corner is occupied by a −3.0-μC charge

Naddik [55]

Answer:

4.30 x 10⁵ N/C

Explanation:

Two positive +3.0-μC point charges at opposite corners of the square creates equal and opposite electric field at the center. hence the electric field by these two positive charges at opposite corners becomes zero.

$a$ = length of the square of side = 0.50 m

$r$ = distance of the center from each corner = $\frac{a}{sqrt(2)} = \frac{0.50}{sqrt(2)} = 0.354 m$

Magnitude of net electric field at the center is given as

$E = \frac{2kq}{r^{2}} \\E = \frac{2(8.99\times10^{9})(3\times10^{-6})}{(0.354)^{2}} \\E = 4.30\times10^{5} NC^{-1}$

6 0

3 years ago

What electric field strength would store 12.5 JJ of energy in every 6.00 mm3mm3 of space?

Tcecarenko [31]

To develop this problem we will apply the concepts related to the potential energy per unit volume for which we will obtain an energy density relationship that can be related to the electric field. From this formula it will be possible to find the electric field required in the problem. Our values are given as

The potential energy, $U = 13.0 J$

The volume, $V = 6.00 mm^3 = 6.00*10^{-9}m^3$

The potential energy per unit volume is defined as the energy density.

$u = \frac{U}{V}$

$u= \frac{(13.0 J)}{(6.00*10^{-9} m^3)}$

$u= 2.167109 J/m^3$

The energy density related with electric field is given by

$u = \frac{1}{2} \epsilon_0 E^2$

Here, the permitivity of the free space is

$\epsilon_0 = 8.85*10^-{12} C^2/N \cdot m^2$

Therefore, rerranging to find the electric field strength we have,

$E = \sqrt{\frac{2u}{\epsilon_0}}$

$E = \sqrt{\frac{2(2.167109)}{8.85*10^{-12}}}$

$E = 2.211010 V/m$

Therefore the electric field is 2.21V/m

8 0

3 years ago

What is the momentum of a 5 kg object that has a velocity of 1.2 m/s? 3.8 kg • m/s 4.2 kg • m/s 6.0 kg • m/s 6.2 kg • m/s

Gnesinka [82]

Answer:

Your answer will be 6.0kg•m/s

Explanation:

In the given question all the required details d given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.We know the equation of finding momentum asMomentum = mass * velocity = 5 * 1.2 = 6So the momentum of the object is 6 Newton.

4 0

3 years ago

Read 2 more answers

Which of the following is an example of the Doppler effect?

Oliga [24]

b is your answers in this thread

3 0

2 years ago

On James’s MP3 player, he has 12 sad songs and 40 upbeat songs that he wants to put into playlists. He wants to have the same nu

Anna [14]

Answer:

i would say a) two playlists