Answer:
e.)At twice the distance, the strength of the field is E/4.
Explanation:
The strength of the electric field at a certain distance from a point charge is given by:

where
k is the Coulomb's constant
Q is the charge
r is the distance from the point charge
In this problem, the distance from the point charge is doubled:
r' = 2r
So the new electric field strength is

so, at twice the distance the strength of the field is E/4.
Answer:
The value of radiation pressure is
Pa
Explanation:
Given:
Intensity

Area of piece

From the formula of radiation pressure in terms of intensity,

Where
radiation pressure,
speed of light
We know value of speed of light,

Put all values in above equation,

Pa
Therefore, the value of radiation pressure is
Pa
Answer: 6.47m/s
Explanation:
The tangential speed can be defined in terms of linear speed. The linear speed is the distance traveled with respect to time taken. The tangential speed is basically, the linear speed across a circular path.
The time taken for 1 revolution is, 1/3.33 = 0.30s
velocity of the wheel = d/t
Since d is not given, we find d by using formula for the circumference of a circle. 2πr. Thus, V = 2πr/t
V = 2π * 0.309 / 0.3
V = 1.94/0.3
V = 6.47m/s
The tangential speed of the tack is 6.47m/s
Explanation:
it can be used to show how the parts of the cycle relate to one another
I would say option D, it depends on the size of the star