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Colt1911 [192]
2 years ago
10

How much heat energy is required to raise the temperature of 5 kilograms of coal from 20°C to 220°C? A. 314 J B. 6,573 J C. 1,31

4,718 J D. 4,187,000 J
Physics
2 answers:
liq [111]2 years ago
8 0

Answer:

C. 1,314,718 J

Explanation:

The heat energy needed to raise the temperature of the coal is given by:

Q=m C_s \Delta T

where:

m = 5 kg is the mass of the coal

C_s = 1314 J/kg ^{\circ}C is the specific heat of coal

\Delta T= 220^{\circ}C-20^{\circ}C=200^{\circ}C is the increase in temperature

Substituting into the formula, we find

Q=(5 kg)(1314 J/kg ^{\circ}C )(200^{\circ}C)=1,314,000 J

So, the closest option is

C. 1,314,718 J


Vika [28.1K]2 years ago
3 0
Just took the test and the answer is <span>C. 1,314,718.

</span>
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1\D. Both A and C

2\A true

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a swimmer experiences a total (absolute) pressure of 117,500 pa in a pool. how far below the surface are they located?
marta [7]

Answer:

Explanation:

We know that the pressure can be calculated in the following way:

p = d·g·h

with d being the density of the water, g the gravitational acceleration and h the depth.

Also d of the water = 1000 kg/m^3 circa and g = 9.8 m/s^2 circa

117,500 Pa = 1000kg/m³ · 9.8m/s² · h

Therefore h = 11,9 m

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2 years ago
a car accelerates from rest to a velocity of 5meters/second in 4 seconds. what is its average acceleration over this period of t
Pani-rosa [81]

Answer:

1.25 m/s²

Explanation:

Average acceleration is the change in velocity over change in time.

a = Δv / Δt

a = (5 m/s − 0 m/s) / 4 s

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6 0
3 years ago
A spring whose stiffness is 980 N/m has a relaxed length of 0. 50 m. If the length of the spring changes from 0. 25 m to 0. 81 m
Gelneren [198K]

151.9j

Explanation:

PE=1/2kx^2

PE=1/2(980)(.50)= 245j

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8 0
2 years ago
A gas storage cylinder in an ordinary chemical laboratory measures wide and high. This is the label on it. Contents: gas Pressur
zhenek [66]

Complete Question

A gas storage cylinder in an ordinary chemical laboratory measures 3.5 cm wide and 9.2 cm high with this label on it:

Contents: N2 Gas

Pressure 18.6 atm

If the cylinder is opened and the gas allowed to escape into a large empty plastic bag, what will be the final volume of nitrogen gas, including what’s collected in the plastic bag and what’s left over in the cylinder?

Use 1 atm for the gas final pressure

Answer:

The final volume is 1647.03cm³ or 1.65 litres

Explanation:

Given

Width of cylinder, W = 3.5 cm

Height of Cylinder, H = 9.2 cm

Gas Initial Pressure, P1 = 18.6 atm

Gas Final Pressure, P2 = 1 atm

First, the initial volume of gas has to be calculated to known the quantity of gas before gas outflow

Volume of Gas, V = Volume of a cylinder

V = πr²h

Given the the width of the cylinder is 3.5cm

This means that the diameter of the cylinder is also 3.5cm

Hence; Diameter, D = 3.5cm

Radius, r = ½D

r = ½ * 3.5cm

r = 1.75cm

So, V1 = πr²h becomes

V1 = π * 1.75² * 9.2

V1 = 28.175π cm³

V1 = 88.55 cm³

From Ideal Gas Law;

PV = nRT

Where k = PV (From Boyle's Law)

P1V1 = P2V2 ---- Make V2 the subject of formula

V2 = (P1V1)/P2

Where P1,P2,V1 and V2 represent the initial pressure, final pressure, initial volume and final volume, respectively.

Recall that P1 = 18.6 atm

P2 = 1 atm

V1 = 88.55 cm³

Final volume, V2 = (P1V1)/P2

V2 = (18.6 atm * 88.55 cm³)/1 atm³

V2 = 1647.03cm³

Convert to Litre

V2 = 1647.03/1000

V2 = 1.64703 litres

V2 = 1.65 L

Hence, the final volume is 1647.03cm³ or 1.65litres

8 0
3 years ago
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