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Colt1911 [192]
3 years ago
10

How much heat energy is required to raise the temperature of 5 kilograms of coal from 20°C to 220°C? A. 314 J B. 6,573 J C. 1,31

4,718 J D. 4,187,000 J
Physics
2 answers:
liq [111]3 years ago
8 0

Answer:

C. 1,314,718 J

Explanation:

The heat energy needed to raise the temperature of the coal is given by:

Q=m C_s \Delta T

where:

m = 5 kg is the mass of the coal

C_s = 1314 J/kg ^{\circ}C is the specific heat of coal

\Delta T= 220^{\circ}C-20^{\circ}C=200^{\circ}C is the increase in temperature

Substituting into the formula, we find

Q=(5 kg)(1314 J/kg ^{\circ}C )(200^{\circ}C)=1,314,000 J

So, the closest option is

C. 1,314,718 J


Vika [28.1K]3 years ago
3 0
Just took the test and the answer is <span>C. 1,314,718.

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To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:

Mass of copper wire(m) = 1.10g = 1.10*10^{-3} kg

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Resistance (R) = 0.390\Omega

Volume is defined as,

V= lA \text{ and }\frac{m}{\rho}

lA= \frac{1.10*10^{-3}}{8.92*10^3}

lA = 1.233*10^{-7} m^3 (1)

We know that,

\frac{l}{A} = \frac{R}{\gamma}

\frac{l}{A}= \frac{0.390\Omega}{1.7*10^{-8}\Omega m}

\frac{l}{A} = 2.2941*10^7 m^{-1} (2)

Multiplying equation we have

l^2 = (1.233*10^{-7})( 2.2941*10^7)

l^2 = 2.8286m^2

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When the current in a toroidal solenoid is changing at a rate of 0.0240 A/s , the magnitude of the induced emf is 12.4 mV . When
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Answer:

The number of turns in the solenoid is 230.

Explanation:

Given that,

Rate of change of current, \dfrac{dI}{dt}=0.0240\ A/s

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Current, I = 1.5 A

Magnetic flux, \phi=0.00338\ Wb

The induced emf through the solenoid is given by :

\epsilon=L\dfrac{dI}{dt}

or

L=\dfrac{\epsilon}{(di/dt)}........(1)

The self inductance of the solenoid is given by :

L=\dfrac{N\phi}{I}.........(2)

From equation (1) and (2) we get :

\dfrac{\epsilon}{(di/dt)}=\dfrac{N\phi}{I}

N is the number of turns in the solenoid

N=\dfrac{\epsilon I}{\phi (dI/dt)}

N=\dfrac{12.4\times 10^{-3}\times 1.5}{0.00338 \times 0.024}

N = 229.28 turns

or

N = 230 turns

So, the number of turns in the solenoid is 230. Hence, this is the required solution.

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Bob and John are pulling in different directions. If Bob is pulling to the right with a force of 10N, and John is pulling to the
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A piece of metal has a mass of 9.00 kg. If it displaces water that fills a container 10.0 cm x 10.0 cm x 10.0 cm, what is the ma
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Answer:

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D = 9000 kg/m³

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