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kramer
3 years ago
5

What provides the power to move the cutting blade on a sawmill?

Physics
2 answers:
Lynna [10]3 years ago
3 0
Sawmills rely on electricity to run the cutting blade.
yanalaym [24]3 years ago
3 0

Answer: electrical energy

Explanation:

In old days, the saw was run manually. Nowadays, the saw is connected to motor.

A sawmill is connected to power source from where it draws electricity

The electrical energy is converted to mechanical energy by motor which runs the blade of the sawmill. Then the blade cuts the wood into logs.

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Answer:

Parallel combination.

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A uniform marble rolls down a symmetrical bowl, start- ing from rest at the top of the left side. The top of each side is a dist
Paha777 [63]

Answer:

Part a)

h' = \frac{10}{14} h

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

h' = \frac{10}{14} h

so on smooth it will go to lower height

Explanation:

As we know by energy conservation the total energy at the bottom of the bowl is given as

\frac{1}{2} mv^2 + \frac{1}{2}I\omega^2 = mgh

here we know that on the left side the ball is rolling due to which it is having rotational and transnational both kinetic energy

now on the right side of the bowl there is no friction

so its rotational kinetic energy will not change and remains the same

so it will have

\frac{1}{2}mv^2 = mgh'

now we know that

I = \frac{2}{5}mr^2

\omega = \frac{v}{r}

so we have

\frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = mgh

\frac{1}{2}mv^2 + \frac{1}{5}mv^2 = mgh

\frac{7}{10}mv^2 = mgh

\frac{1}{2}mv^2 = \frac{10}{14}mgh

so the height on the smooth side is given as

h' = \frac{10}{14} h

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

h' = \frac{10}{14} h

so on smooth it will go to lower height

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3 years ago
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"paying bills online instead of sending paper through mail"
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Answer:

The ladder is 3.014 m tall.

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If we plug in the values we are given for the problem, we get:

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To solve this equation for x (the height of the ladder), we must multiply both sides by 1.37. If we do this, we get:

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