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Anni [7]
2 years ago
8

Heat flows naturally from objects that have higher energy to those with?

Chemistry
1 answer:
Vlad [161]2 years ago
8 0

Answer:

heat flow

Explanation:

heat flow moves to a higher temperature to a lower temperature

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Which chemical equation demonstrates the law of conservation of mass!
zlopas [31]

Answer:

F. 2NO + 02 —> 2NO

H. 4NH3 + 502 —> 4NO + 6H20

Explanation:

The law of conservation of mass states that matter can neither be created nor destroyed during a chemical reaction but can be convert from one form to another.

2NO + 02 —> 2NO

From the above, the total number of N on the left balance the total number on the right i.e 2 atoms of N on both side of the equation.

The total number of O on the left balance the total number on the right i.e 2 atoms of O on both side of the equation. This is certified by the law of conservation of mass.

4NH3 + 502 —> 4NO + 6H20

From the above, the total number of N on the left balance the total number on the right i.e 4 atoms of N on both side of the equation.

The total number of O on the left balance the total number on the right i.e 10 atoms of O on both side of the equation.

The total number of H on the left balance the total number on the right i.e 12 atoms of O on both side of the equation.

This is certified by the law of conservation of mass.

The rest equation did not conform to the law of conservation of mass as the atoms on the left side did not balance those on the right side

5 0
3 years ago
Which of the following is a nonrenewable resource?
maks197457 [2]

Answer:

I think the answer is A!!!

3 0
3 years ago
Read 2 more answers
HELP PLEASE (Solve this problem using the appropriate law). what is the volume of 0.382 moles of hydrogen gas at 1.50 atmosphere
kaheart [24]

Answer:

V = 6.17 L

Explanation:

Given data:

Volume = ?

Number of moles = 0.382 mol

Pressure = 1.50 atm

Temperature = 295 k

R = 0.0821 L. atm. /mol. k

Solution:

According to ideal gas equation:

PV= nRT

V = nRT/P

V = 0.382 mol × 0.0821 L. atm. /mol. k ×295 k / 1.50 atm

V = 9.252  L. atm.  / 1.50 atm

V = 6.17 L

5 0
3 years ago
Day 2 code word
bagirrra123 [75]

Answer:

chloroplast

Explanation:

4 0
3 years ago
What is the new pressure if the temperature outside is 296k and his weight causes the tire's volume to drop to 2.0 liters
sukhopar [10]

Question:

At standard temperature and pressure, the volume of a tire is 3.5L. What is the new pressure if the temperature outside is 296k and its weight causes the volume of the gas is 2.0 L?

Answer:

The new pressure is: 1.896 atm

Explanation:

At standard temperature and pressure, we have:

P_1 = 1atm

T_1 = 273.15k

V_1 = 3.5L

Outside, we have:

T_2 = 296k

V_2 = 2.0L

Required

Determine the new pressure

Using combined gas law, we have:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

This gives:

\frac{1 * 3.5}{273.15} =\frac{P_2*2.0}{296}

Solve for P_2

P_2 = \frac{296 * 1 * 3.5}{273.15*2.0}

P_2 = \frac{1036}{546.30}

P_2 \approx 1.896 atm

7 0
3 years ago
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