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sleet_krkn [62]
2 years ago
5

A force vector F1 points due east and has a magnitude of 200 Newtons, A second force F2 is added to F1. The resultant of the two

vectors has a magnitude of 400 newtons and points along the due east/west line. Find the magnitude and direction of F2. Note that there are two answers.
Physics
1 answer:
Andrew [12]2 years ago
4 0
A force vector F1 points due east and has a magnitude of 200 Newtons, A second force F2 is added to F1. The resultant of the two vectors has a magnitude of 400 newtons and points along the due east/west line. Find the magnitude and direction of F2. Note that there are two answers. <span>The given values are
F1 = 200 N</span> F2 =? Total = 400 N

Solution: F1 + F2 = T 200 N + F2 = 400N
F2 = 400 - 200
F2 = 200 N



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\huge\mathfrak\red{✔Answer:-}

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Alex

Answer:

b. Constant magnitude, but varying direction, perpendicular to the equipotential.

Explanation:

As we know that the relation between electric field and electric potential is given as

\Delta E = -\frac{dV}{dr}

here if we say that potential is constant because electric field sensor is moving along equi-potential line.

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<h2>velocity = 12.73 km/hr.</h2><h2 />

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5 0
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Answer:

No

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If one lap around the track is 400 m and the sprinter ran 1 lap around the track. Then the sprinter's distance is 400 m and their displacement is 0 m

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