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3 years ago

Help!! Help!! Help!! Help!!

Physics

1 answer:

Mice21 [21]3 years ago

3 0

I think it's Quadratic. With all the rapid increase of the values of y.

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3 years ago

Which is a tool used by scientists to determine the composition of objects?

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Explanation:

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A machine has an efficiency of 70%. How much work dose the machine do when 20,000 J of work is done on it ?

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3 years ago

Boltzmann’s constant is 1.38066×10−23 J/K, and the universal gas constant is 8.31451 J/K · mol. If 1.9 mol of a gas is confined

Crazy boy [7]

Answer:

The average kinetic energy of a gas molecule is 8.49 × 10⁻²¹ J

Explanation:

According to Kinetic Molecular Theory, the average kinetic energy of gas molecules is a function only of temperature and is given by the equation:

$E=\frac{3}{2}kT$

$pV=nRT;\\T=\frac{pV}{nR}$

Substituting the value of T in the kinetic energy equation:

$E=\frac{3kpV}{2nR}$

Where p is the pressure of the gas = 9 atm = 9 × 101325 pa

k is the Boltzmann’s constant = 1.38066 × 10⁻²³ J/K,

V is the volume of the gas = 7.1 L = 7.1 × 10⁻³ m³

n is the number of moles of the gas = 1.9 mol

R is the universal gas constant = 8.31451 J/K · mol.

E is the average kinetic energy of a gas molecule

Substituting values:

$E=\frac{3kpV}{2nR}=\frac{3*1.38066*10^{-23}*9*101325*7.1*10^{-3}}{2*1.9*8.31451}=8.49*10^{-21}J$

The average kinetic energy of a gas molecule is 8.49 × 10⁻²¹ J

6 0

3 years ago

. A proton, which moves perpendicular to a magnetic field of 1.2 T in a circular path of radius 0.080 m, has what speed? (qp = 1

almond37 [142]

Answer:

$9.198\times 10^6 m/s$

Explanation:

We are given that

Magnetic field, B=1.2 T

Radius of circular path, r=0.080 m

$q_p=1.6\times 10^{-19} C$

$m_p=1.67\times 10^{-27} kg$

$\theta=90^{\circ}$

We have to find the speed of proton.

We know that

Magnetic force, F= $qvBsin\theta$

According to question

Magnetic force=Centripetal force

$q_pvBsin90^{\circ}=\frac{m_pv^2}{r}$

$1.6\times 10^{-19}\times 1.2=\frac{1.67\times 10^{-27}v}{0.08}$

$v=\frac{1.6\times 10^{-19}\times 1.2\times 0.08}{1.67\times 10^{-27}}$

$v=9.198\times 10^6 m/s$

5 0

4 years ago