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3 years ago

Help!! Help!! Help!! Help!!

Physics

1 answer:

Mice21 [21]3 years ago

3 0

I think it's Quadratic. With all the rapid increase of the values of y.

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Once you have picked a standard by the very meaning of atandard it is invariable.

Dominik [7]

Answer:

düz devam sağa dön bı tane Kabe var

7 0

4 years ago

A radar used to detect the presence of aircraft receives a pulse that has reflected off an object 5 ✕ 10−5 s after it was transm

Sunny_sXe [5.5K]

Answer:

7500 m

Explanation:

The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.

We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so

d = 2L

In a time of

$t=5\cdot 10^{-5}s$

Electromagnetic waves travel in a vacuum at the speed of light, which is equal to

$c=3.0\cdot 10^8 m/s$

Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:

$d=vt$ (1)

where

$v=c=3.0\cdot 10^8 m/s$

$t=5\cdot 10^{-5}s$

$d=2L$ , where L is the distance between the radar and the object

Re-arranging eq(1) and substituting, we find L:

$L=\frac{vt}{2}=\frac{(3.0\cdot 10^8)(5\cdot 10^{-5})}{2}=7500 m$

7 0

4 years ago

Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart

Romashka [77]

Answer:

E = 5291.00 N/C

Explanation:

Expression for capacitance is

$C = \frac{\epsilon A}{d}$

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

$C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}$

$C = 24.06 \epsilon$

$C = 24.06\times 8.854\times 10^{-12} F$

$C =2.1\times 10^{-10} F$

We know that capacitrnce and charge is related as

$V = \frac{Q}{C}$

$= \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}$

v = 9.523 V

Electric field is given as

$E = \frac{V}{d}$

= $\frac{9.52}{1.8*10^{-3}}$

E = 5291.00 V/m

E = 5291.00 N/C

5 0

3 years ago

What are many scientific laws represented with?

salantis [7]

hypothesises i think

3 0

4 years ago

A two-dimensional object placed in the xy-plane has three forces acting on it: a force of 3.0 n along the x-axis acting at a poi

Anastasy [175]

the net torque about the point (-1 m, 1 m) is 4 N-m.

The resultant force acting on the object is calculated as

R^2=(-5+3)^2+2^2=2.82 N

Distance of the point from the resultant force

d^2=(-1)^2+1^2=1.414

The net torque acting on the point (-1 m, 1 m) is

T=2.82×1.41=3.98 N-m

3 0

4 years ago