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3 years ago

What is the purpose of zigzag line on a periodic table ?

Physics

1 answer:

LekaFEV [45]3 years ago

4 0

The zigzag line on the periodic table separates the metals from the nonmetals.

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Suppose that an object is moving along a vertical line. Its vertical position is given by the equation L(t) = 2t3 + t2-5t + 1, w

Tatiana [17]

Answer:

The average velocity is

$266\frac{m}{s},274\frac{m}{s}$ and $117\frac{m}{s}$ respectively.

Explanation:

Let's start writing the vertical position equation :

$L(t)=2t^{3}+t^{2}-5t+1$

Where distance is measured in meters and time in seconds.

The average velocity is equal to the position variation divided by the time variation.

$V_{avg}=\frac{Displacement}{Time}$ = Δx / Δt = $\frac{x2-x1}{t2-t1}$

For the first time interval :

t1 = 5 s → t2 = 8 s

The time variation is :

$t2-t1=8s-5s=3s$

For the position variation we use the vertical position equation :

$x2=L(8s)=2.(8)^{3}+8^{2}-5.8+1=1049m$

$x1=L(5s)=2.(5)^{3}+5^{2}-5.5+1=251m$

Δx = x2 - x1 = 1049 m - 251 m = 798 m

The average velocity for this interval is

$\frac{798m}{3s}=266\frac{m}{s}$

For the second time interval :

t1 = 4 s → t2 = 9 s

$x2=L(9s)=2.(9)^{3}+9^{2}-5.9+1=1495m$

$x1=L(4s)=2.(4)^{3}+4^{2}-5.4+1=125m$

Δx = x2 - x1 = 1495 m - 125 m = 1370 m

And the time variation is t2 - t1 = 9 s - 4 s = 5 s

The average velocity for this interval is :

$\frac{1370m}{5s}=274\frac{m}{s}$

Finally for the third time interval :

t1 = 1 s → t2 = 7 s

The time variation is t2 - t1 = 7 s - 1 s = 6 s

Then

$x2=L(7s)=2.(7)^{3}+7^{2}-5.7+1=701m$

$x1=L(1s)=2.(1)^{3}+1^{2}-5.1+1=-1m$

The position variation is x2 - x1 = 701 m - (-1 m) = 702 m

The average velocity is

$\frac{702m}{6s}=117\frac{m}{s}$

5 0

3 years ago

Which of the following has the fewest calence electrons?

dlinn [17]

Answer:

both magnesium and strontium have 2 valence electrons

Explanation:

potassium has 8 valence electrons, and nitrogen has 5.

8 0

3 years ago

a car drives 40 miles east, turns around, then drives 30 miles west. (a) Find the distance traveled by the car. (b) find the car

Dovator [93]

Part A)

Distance is given as sum of total path length

So here as we are given that car drives 40 miles East and 30 miles West

So here the total path length is

$Distance = 40 miles + 30 miles$

$distance = 70 miles$

Part B)

Displacement is given as straight line distance between initial and final position

So here we can see that

$d_1 = 40 miles$ East

$d_2 = 30 miles$ West

Now the total displacement will be

$d = d_1 - d_2 = 40 - 30 = 10 miles$

<u><em>so the displacement will be 10 miles East</em></u>

8 0

3 years ago

What will happen to the ball in example C if there is no friction?

Sloan [31]

Answer:

A) The ball will roll forever in a straight path.

8 0

3 years ago

Alguém tem a resposta ?

Maru [420]

The answer is D or C

3 0

3 years ago