Answer:
a. A list of the names of each student present today. (microstate)
b. The number of students in attendance. (macrostate)
Explanation:
You can fins the answer to this question by comparing the situation of the problem with a system of molecules with discrete energy.
Without importance of which molecules have a specific energy, but rather, what is the total amount of energy, you can get for different configurations of energy the same amount of the total energy. If different configurations of the energies of the molecules give you the same total energy of the system, you say that the macrostate is the same. In the case of the classroom, it does not matter how are distributed the students in the class, the total number of students is always the same. The macrostate is the same for what ever organization of the students in the class.
If you would interested in the energy of each molecules, you will obtain different configurations. In the case of the classroom. The names of the student will define a microstate because in this case there are many configurations.
a. A list of the names of each student present today. (microstate)
b. The number of students in attendance. (macrostate)
Answer:
Explanation:
Velocity will be equal to the area under the curve of the acceleration-time plot.
v = ½(45)(0.075) = 1.6875
v = 1.7 m/s
h = (0² - 1.6875²) / (2(-9.8)) = 0.145288...
h = 15 cm
Answer:
true I, II and III
Explanation:
The force is a vector quantity, by local it must be added as vectors, we can suppose several cases
.i) the vectors are colonial, so their sum is maximum
F_max = 9 + 15 + 18
F_max = 42 N
This is the maximum value
ii) the anti-parallel vectors giving a minimum value
F_min = 15 + 9-18
F_min = 6 N
iii) the vectors have angles between them, so we must use the Pythagorean theorem to find the resultant, which is an intermediate value between the two extreme values found.
Let's take a look at each statement
I) True This is the maximum value of the force if all the vectors are colonial
II) True The minimum value is 6 N, so zero can never be reached
III) True these bores are between the maximum values and the direction of the vectors, lower values occur when the forces have angular between them
IV) False. Force can never reach zero
V) False. Several of the above are conclusions of the exercise
The de - acceleration of bullet from 360 m/s after it struck the tree trunk and was brought to rest is -152.54 x 10⁴ m/s².
<h3>What is Acceleration in Kinematics?</h3>
Acceleration is defined as the rate of change of velocity with respect to time. Mathematically -
<h3>a = Δv/Δt</h3>
Given is a bullet initially travelling at 360 m/s struck into a tree trunk 8.5 cm inside and comes to rest. From this, we can write
initial velocity [u] = 360 m/s
final velocity [v] = 0 m/s
distance travelled [d] = 8.5 cm = 0.085 m
The time span after which bullet comes to rest will be -
Δt = d/u
Δt = 0.085/360 = 2.36 x 10 ⁻⁴ seconds
a = Δv/Δt
Δv = 0 - 360 = - 360 m/s
a = (v - u)/Δt
a = - 360/(2.36 x 10 ⁻⁴)
a = - 152.54 x 10⁴ m/s²
Therefore, the de - acceleration of bullet from 360 m/s after it struck the tree trunk and was brought to rest is -152.54 x 10⁴ m/s².
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Answer:
the first answer is correct
