Answer:
Explanation:
The velocity at the inlet and exit of the control volume are same 
Calculate the inlet and exit velocity of water jet
The conservation of mass equation of steady flow
since inlet and exit velocity of water jet are equal so the inlet and exit cross section area of the jet is equal
The expression for thickness of the jet
R is the radius
t is the thickness of the jet
D_j is the diameter of the inlet jet
(b)
![R-x=\rho(AV_r)[-(V_i)+(V_c)\cos 60^o]\\\\=\rho(V_j+V_c)A[-(V_i+V_c)+(V_i+V_c)\cos 60^o]\\\\=\rho(V_j+V_c)(\frac{\pi}{4}D_j^2 )[V_i+V_c](\cos60^o-1)]](https://tex.z-dn.net/?f=R-x%3D%5Crho%28AV_r%29%5B-%28V_i%29%2B%28V_c%29%5Ccos%2060%5Eo%5D%5C%5C%5C%5C%3D%5Crho%28V_j%2BV_c%29A%5B-%28V_i%2BV_c%29%2B%28V_i%2BV_c%29%5Ccos%2060%5Eo%5D%5C%5C%5C%5C%3D%5Crho%28V_j%2BV_c%29%28%5Cfrac%7B%5Cpi%7D%7B4%7DD_j%5E2%20%29%5BV_i%2BV_c%5D%28%5Ccos60%5Eo-1%29%5D)
![R_x=[1000\times(44)\frac{\pi}{4} (10\times10^{-3})^2[(44)(\cos60^o-1)]]\\\\=-7603N](https://tex.z-dn.net/?f=R_x%3D%5B1000%5Ctimes%2844%29%5Cfrac%7B%5Cpi%7D%7B4%7D%20%2810%5Ctimes10%5E%7B-3%7D%29%5E2%5B%2844%29%28%5Ccos60%5Eo-1%29%5D%5D%5C%5C%5C%5C%3D-7603N)
The negative sign indicate that the direction of the force will be in opposite direction of our assumption
Therefore, the horizontal force is -7603N
Answer:
Explanation:
Depression = .75 x 10⁻² m
Load = 120 g
Spring constant = 120g / .75 x 10⁻²
= 160 x 10² g / m
b )
Depression by player
= .48 x 10⁻² m
His weight
= .48 x 10⁻² x 160 x 10² g
= 76.8 kg
So he is eligible.
Answer: a) 8.2 * 10^-8 N or 82 nN and b) is repulsive
Explanation: To solve this problem we have to use the Coulomb force for two point charged, it is given by:
Replacing the dat we obtain F=82 nN.
The force is repulsive because the points charged have the same sign.
Answer:
If the distance is doubled, the force of gravity between the two bodies is one-fourth as strong as before
Explanation:
The force of gravity between two bodies depends on the mass and distance. But we will focus on distance since that's what the question asks
Therefore, the force of gravity decreases as distance between the bodies increases.
