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RUDIKE [14]
3 years ago
9

A gas has a temperature of 273.15 k and a pressure of 101.325 kpa. what can be concluded about the gas?

Chemistry
2 answers:
FromTheMoon [43]3 years ago
5 0
We are given with a <span>temperature of 273.15 Kelvin and a pressure of 101.325 kPa. Using PV=nRT rule of ideal gas, where P is pressure, V is volume, n is the number of moles, R is the gas constant and T is temperature, we can conclude that the conditions are under STP(standard temp and pressure) and one mole of this gas occupies 22.4 L of volume.</span>
Mama L [17]3 years ago
5 0

Answer : A gas has a temperature of 273.15 K and a pressure of 101.325 kPa from this we conclude that the gas reached at standard temperature and pressure.

Explanation :

STP : STP stands for standard temperature and pressure.

At STP,

The temperature is, 0^oC or 273.15K or 32^oF

The pressure is, 1atm or 101.325kPa

The volume is, 22.4 L

As per question we conclude that, when the temperature and pressure of the gas will be 273.15 K and 101.325 kPa respectively this means that the gas reached at standard temperature and pressure.

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