Question

A gas has a temperature of 273.15 k and a pressure of 101.325 kpa. what can be concluded about the gas?

Answer 1

We are given with a temperature of 273.15 Kelvin and a pressure of 101.325 kPa. Using PV=nRT rule of ideal gas, where P is pressure, V is volume, n is the number of moles, R is the gas constant and T is temperature, we can conclude that the conditions are under STP(standard temp and pressure) and one mole of this gas occupies 22.4 L of volume.

Answer 2

Answer : A gas has a temperature of 273.15 K and a pressure of 101.325 kPa from this we conclude that the gas reached at standard temperature and pressure.

Explanation :

STP : STP stands for standard temperature and pressure.

At STP,

The temperature is, $0^oC$ or $273.15K$ or $32^oF$

The pressure is, $1atm$ or $101.325kPa$

The volume is, 22.4 L

As per question we conclude that, when the temperature and pressure of the gas will be 273.15 K and 101.325 kPa respectively this means that the gas reached at standard temperature and pressure.