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Evgen [1.6K]
3 years ago
5

Using the periodic table, predict the classification of iodine and elaborate on the reasoning. A) Iodine is a noble gas and has

a full valence electron shell, is chemically non-reactive, colorless, odorless, and is a gas at room temperature. B) Iodine is a metal and is shiny, malleable, ductile, conducts heat and electricity, forms basic oxides, and forms cations in aqueous solution. C) Iodine is a nonmetal and is dull, brittle, poor conductor of heat and electricity, forms anions in aqueous solution, and is a solid at room temperature. D) Iodine is a metalloid and has properties of both metals and nonmetals - it appears lustrous, but is brittle and a poor conductor of heat and electricity.
Chemistry
2 answers:
Sonja [21]3 years ago
7 0
C: Its not A because it is not a noble gas as it doesn't have a full valence shell, its missing 1 electron. Its not B because iodine is not a metal and its not D because it is not a metalloid. But it is C because it does form anions and is a non metal
NNADVOKAT [17]3 years ago
7 0

Answer: Option (C) is the correct answer.

Explanation:

Iodine belongs to halogen group and it is a non-metal.

Some properties of iodine are as follows.

  • It is dull.
  • Being a non-metal iodine is brittle.
  • It is a poor conductor of of heat and electricity.
  • Iodine form anions in aqueous solution.
  • Iodine is a solid at room temperature.
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Explanation:

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My science homework is due tomorrow and I am stuck on this last question.
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4 years ago
Extend your thinking: The slow decay of radioactive materials can be used to find the age of rocks, fossils, and archaeological
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The age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

<h3>What is the half-life of a radioactive material?</h3>

The half-life of a radioactive material is the time taken for half the atoms present in the material to decay or disintegrate.

The half-life, t_\frac{1}{2}, the age, t, and amount remaining, A_{r}, of a radioactive material are related by the formula below:

  • t = \frac{t_\frac{1}{2}*A_{r}}{-ln2}

Half-life of carbon-14 = 6000 years

For the Egyptian papyrus with 63% of its original carbon-14 atoms:t = \frac{6000*0.63}{-0.63} = 4000\:years

For the Aboriginal charcoal with 22% of its original carbon-14 atoms:

t = \frac{6000*0.22}{-0.63} = 13106.5\:years

For the Mayan headdress with 79% of its original carbon-14 atoms:

t = \frac{6000*0.79}{-0.63} = 2040\:years

Neanderthal skull with 3% of its original carbon-14 atoms:

t = \frac{6000*0.03}{-0.63} = 30353\:years

Therefore, the age in years of the Egyptian papyrus, the Aboriginal charcoal, the Mayan headdress, and the Neanderthal skull are 4000 years, 13106.5years , 2040 years, and 30353 years respectively.

Learn more about half-life at: brainly.com/question/26689704

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6 0
2 years ago
A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu
OLEGan [10]

Answer: The final temperature of nickel and water is  25.2^{o}C.

Explanation:

The given data is as follows.

   Mass of water, m = 55.0 g,

  Initial temp, (t_{i}) = 23^{o}C,      

  Final temp, (t_{f}) = ?,

  Specific heat of water = 4.184 J/g^{o}C,      

Now, we will calculate the heat energy as follows.

           q = mS \Delta t

              = 55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)

Also,

    mass of Ni, m = 15.0 g,

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   Final temperature, t_{f} = ?

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Hence, we will calculate the heat energy as follows.

          q = mS \Delta t

             = 15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)      

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

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55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C) = -(15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C))

       t_{f} = \frac{25.9^{o}C}{1.029}

                 = 25.2^{o}C

Thus, we can conclude that the final temperature of nickel and water is  25.2^{o}C.

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