<em><u>general formula RCOX, where R represents an alkyl or aryl organic radical group, CO ... represents a halogen atom such as chlorine ... loss of a hydroxyl group (-OH), viz, acetyl,. CH, CO- ..</u></em>

8 0

2 years ago

How many grams of water can be produced when 11.7 moles of ethane (C2H6) react with excess oxygen gas?

Elina [12.6K]

Answer: 631.8 g

Explanation:

$2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O$

It can be seen from the balanced chemical equation, 2 moles of ethane reacts with 7 moles of Oxygen gas to produce 4 moles of carbon dioxide and 6 moles of water.

Ethane is the limiting reagent as it limits the formation of product.

Thus, if 2 moles of ethane produce 6 moles of water.

11.7 moles moles of ethane produce= $\frac{6}{2}\times 11.7=35.1 moles$ of water.

Mass of water= no of moles $\times$ Molar mass

Mass of water= 35.1 $\times$ 18g/mol= 631.8 g

4 0

3 years ago

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