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vichka [17]
4 years ago
7

____ 26. what is the weight percentage of nitrogen in urea, cn2h4o

Chemistry
1 answer:
Paraphin [41]4 years ago
7 0
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100

From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams

therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams

Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
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Answer:

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Know how you would determine the percent yield of a reaction if you have the given amount of the reactants and the amount of the
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4 years ago
In the process of attempting to characterize a substance, a chemist makes the following observations. Which are physical propert
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Answer: a) The substance is a silvery white, lustrous metal :physical property.  

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Explanation:

Chemical property is defined as the property of a substance which is observed during a reaction where the chemical composition identity of the substance gets changed.

Physical property is defined as the property which can be measured and whose value describes the state of physical system. For Example: State, density etc.

a) The substance is a silvery white, lustrous metal is a physical property

b) It melts at 649°C and boils at 1105°C is a physical property.  

c) Its density at 20°C is 1.738 g/cm^3 is a physical property.  

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7 0
4 years ago
A 26.08 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reac
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Answer:

Molar percent of sodium in original mixture is 88,50%

Explanation:

The last reaction is:

BaCl₂ + Na₂SO₄ → BaSO₄ + 2 NaCl

The moles of BaCl₂ are:

0,132L × 3,80M = 0,502 moles of BaCl₂

As the amount of BaCl₂ is the maximum possible to produce BaSO₄, the moles of BaCl₂ must be the same than moles of Na₂SO₄.

0,502 moles of BaCl₂ ≡ 0,502 moles of Na₂SO₄

These moles of Na₂SO₄ comes from:

2 Na + H₂SO₄ → Na₂SO₄ + H₂

As the reaction is in stoichiometric amounts, moles of Na are twice the moles of Na₂SO₄

0,502 moles of Na₂SO₄ ×\frac{2molesNa}{1moleNa_{2}SO_{4}}× 22,99 g/mole = 23,08 g of Na

Molar percent of sodium in original mixture is:

\frac{23,08g}{26,08g}*100 = <em>88,50% </em>

I hope it helps

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4 years ago
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