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vichka [17]
3 years ago
7

____ 26. what is the weight percentage of nitrogen in urea, cn2h4o

Chemistry
1 answer:
Paraphin [41]3 years ago
7 0
Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100

From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams

therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams

Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%
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Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.84×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.14×10−4, what is the
Nimfa-mama [501]

Answer: The value of equilibrium constant for reaction is, 1.42\times 10^{-2}

Explanation:

The given chemical equations are:

(1) PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq) ;  K_3=1.84\times 10^{-10}

(2) AgCl(aq)\rightleftharpoons Ag^{+}(aq)+Cl^-(aq) ;  K_4=1.14\times 10^{-4}

Now we have to calculate the equilibrium constant for chemical equation as:

PbCl_2(aq)+2Ag^{+}(aq)\rightleftharpoons 2AgCl(aq)+Pb^{2+}(aq) ;  K=?

We are reversing reaction 2 and multiplying reaction 2 by 2 and then adding both reaction, we get the final reaction.

The equilibrium constant for the reverse reaction will be the reciprocal of that reaction.

If the equation is multiplied by a factor of '2', the equilibrium constant of that reaction will be the square of the equilibrium constant.

If we are adding equations then the equilibrium constants will be multiplied.

The value of equilibrium constant for reaction is:

K=(\frac{1}{K_4})^2\times K_3

Now put all the given values in this expression, we get:

K=(\frac{1}{1.14\times 10^{-4}})^2\times (1.84\times 10^{-10})

K=1.42\times 10^{-2}

Hence, the value of equilibrium constant for reaction is, 1.42\times 10^{-2}

7 0
3 years ago
How many carbon dioxide molecules must be added to rubp to make a single molecule of glucose?
Pani-rosa [81]

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6 carbon dioxide molecules

Explanation:

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The Calvin cycle is also known as the dark phase of photosynthesis or also called the carbon fixation phase. It is known as the dark phase because it is not light dependent as is the first phase or light phase .

This second stage of photosynthesis fixes the carbon of the absorbed carbon dioxide and generates the precise number of biochemical elements and processes necessary to produce sugar and recycle the remaining material for continuous production.

The Calvin cycle uses the energy produced in the light phase of photosynthesis to fix the carbon dioxide (CO2) carbon in a solid structure such as glucose, in order to generate energy.

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The Calvin cycle produces in six turns a six-carbon glucose molecule and regenerates three RuBP that will be catalyzed again by the RuBisCo enzyme with CO2 molecules for the restart of the Calvin cycle.

The Calvin cycle requires six molecules of CO2, 18 ATP and 12 NADPH produced in the light phase of photosynthesis to produce a glucose molecule and regenerate three RuBP molecules.

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