____ 26. what is the weight percentage of nitrogen in urea, cn2h4o

1 answer:

7 0

Weight percentage of nitrogen can be calculated using the following rule:
weight percentage of nitrogen = (weight of nitrogen / weight of urea) x 100

From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of hydrogen = 1 grams
molecular mass of oxygen = 16 grams

therefore:
mass of nitrogen in urea = 2(14) = 28 grams
mass of urea = 12 + 2(14) + 4(1) + 16 = 60 grams

Substitute with the masses in the equation to get the percentage:
weight percentage of nitrogen = (28/60) x 100 = 46.667%

You might be interested in

True or false: an apple looks red because it absorbs red light?

MAVERICK [17]

Answer:

Explanation:

True

4 0

3 years ago

Read 2 more answers

Assuming it behaves as an ideal gas, calculate the density of sulfur dioxide, so2, at stp.

Arisa [49]

Hello!

At Standard Pressure and Temperature, an ideal gas has a molar density of 0,04464 mol/L.

So, we need to apply a simple conversion factor to calculate the density of Sulfur Dioxide using the molar mass of Sulfur Dioxide.

$\frac{0,04464 mol SO_2}{1 L SO_2}* \frac{64,066 g SO_2}{1 mol SO_2}=2,8599 g/L$

So, the Density of Sulfur Dioxide (SO₂) at STP is 2,8599 g/L

Have a nice day!

6 0

3 years ago

Read 2 more answers

Which law explain why tire pressure increases on a summer day

Musya8 [376]

Boyle's law

I hope this helps

3 0

3 years ago

You have a 28.2-g sample of a metal heated to 95.2°c. you drop it in a calorimeter with 100. g of water at 25.1°c. the final tem

Vlad [161]

The heat lost by the metal should be equal to the heat gained by the water. We know that the heat capacity of water is simply 4.186 J / g °C. Therefore:

100 g * 4.186 J / g °C * (31°C – 25.1°C) = 28.2 g * Cp * (95.2°C - 31°C)

Cp = 1.36 J / g °C

4 0

3 years ago

Multiple covalent bonds may occur in atoms that contain carbon,nitrogen, or

Arisa [49]

Answer: Multiple covalent bonds may occur in atoms that contain carbon,nitrogen, or oxygen.

8 0

3 years ago