Number of particles
combined gas law : P1V1/T1 = P2V2/T2
<u>Answer:</u>
(a): The expression of equilibrium constant is ![K_{eq}=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
(b): The equation to solve the concentration of NO is ![[NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7BK_%7Beq%7D%5Ctimes%20%5BN_2%5D%5Ctimes%20%5BO_2%5D%7D)
(c): The concentration of NO is 0.0017 M.
<u>Explanation:</u>
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term 
(a):
The given chemical equation follows:
The expression for equilbrium constant will be:
(b):
The equation to solve the concentration of NO follows:
......(1)
(c):
Given values:
![[N_2]_{eq}=0.166M](https://tex.z-dn.net/?f=%5BN_2%5D_%7Beq%7D%3D0.166M)
![[O_2]_{eq}=0.145M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D0.145M)
Plugging values in equation 1, we get:
![[NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7B%281.2%5Ctimes%2010%5E%7B-4%7D%29%5Ctimes%200.166%5Ctimes%200.145%7D)
![[NO]=\sqrt{2.88\times 10^{-6}}](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Csqrt%7B2.88%5Ctimes%2010%5E%7B-6%7D%7D)
![[NO]=0.0017 M](https://tex.z-dn.net/?f=%5BNO%5D%3D0.0017%20M)
Hence, the concentration of NO is 0.0017 M.
Answer:
The C-O stretch of phenol
Explanation:
Electron delocalization causes the of the phenol to have partial double bond character, whereas the  of the cyclohexanol is a pure single bond. Again, we know as the bond order or bond strength increases the absorption occurs at larger wave number. So, the  stretch of the phenol occurs at larger wave number.
Answer:
the answer is solid change into liquide.
please mark me as a brainlist..
The chemical equation is said to be balanced if the number of atoms in the reactants and products is the same
<h3>Further explanation</h3>
Equation balanced ⇒ total number of atoms in reactants(on the left)= total number of atoms in products(on the right)
H₂+O₂---> H₂O
Reactants : H₂, O₂
Products : H₂O
not balanced
H₂O₂ ---> H₂O+O₂
Reactants : H₂O₂
Products : H₂O, O₂
not balanced
Na+O₂ ---> Na₂O
Reactants : Na, O₂
Products : Na₂O
not balanced
N₂+H₂ ---> NH₃
Reactants : N₂, H₂
Products : NH₃
not balanced
P₄+O₂---> P₄O₁₀
Reactants : P₄, O₂
Products : P₄O₁₀
not balanced
Fe+H₂O ----> Fe₃O₄ + H₂
Reactants : Fe, H₂O
Products : Fe₃O₄
not balanced
