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OverLord2011 [107]
4 years ago
8

When a strong acid and strong base combine will they form:

Chemistry
1 answer:
sergij07 [2.7K]4 years ago
6 0

Answer: “Salt and Water”.

Explanation: Strong Acids and Strong Bases each disassociate completely.

Sodium Hydroxide(aq) and Nitric Acid(aq):

NaOH -> Na+ + OH-

& HNO3-> H+ + NO3- when combined

Yield Na+ + NO3- + H2O; evaporate off the water, and Sodium Nitrate remains.

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Cubic centimeter is a unit used to measure what ?
Stolb23 [73]
A cubic centimetre (or cubic centimeter in US English) (SI unit symbol: cm3; non-SI abbreviations: cc and ccm) is a commonly used unit of volume that extends the derived SI-unit cubic metre, and corresponds to the volume of a cube that measures 1 cm × 1 cm × 1 cm.
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3 years ago
What should you be careful of when measuring the temperature of a liquid in a beaker
andrezito [222]

The precaution to be taken while measuring the temperature of a liquid in a beaker is applying proper heat balance and taking all the required precautions.

  • A beaker with an open top contains a sample of liquid. It exposes this sample to light.
  • That liquid absorbs the light energy, turning it into heat energy. As a result, the liquid becomes warmer and evaporation is accelerated. As a result, there is less liquid in the beaker.
  • Since it is well known that the surface temperature of a liquid, along with air movement above the liquid surface, is one of the dominant factors affecting evaporation, I want to measure the evaporation rate as a function of surface temperature.
  • This can be done by applying a heat balance.

Learn more about heat balance at:

brainly.com/question/1292905

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3 0
2 years ago
Deposition can occur where wind or running water slows down? true or false
Shalnov [3]

Answer:

The answer is True.

Explanation:

6 0
3 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
If a substance has a half-life of 55.6 s, and if 230.0 g of the substance are present initially, how many grams will remain afte
Assoli18 [71]

Answer:

m=0.127g

Explanation:

Hello,

In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}

In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:

m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g

Best regards.

6 0
3 years ago
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