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MaRussiya [10]
3 years ago
15

An isolated conducting sphere has a 15 cm radius. One wire carries a current of 1.0000046 A into it while another wire carries a

current of 1.0000000 A out of it. How long in seconds would it take for the sphere to increase in potential by 890 V?

Physics
1 answer:
lbvjy [14]3 years ago
7 0

Answer: It would take 3.23ms

Explanation: Please see the attachments below

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A 20kg boy on a 5 kg skateboard coasts to a rest from a speed of 4.5m/s while traveling a distance of 20m on the sidewalk. Draw
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It will take him 4.5 seconds


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The three elements of emotion are?
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Answer: Physical component- state of physiological arousal triggered by autonomic nervous system

Behavioral component- outward expression of emotion, including facial expression and behavior

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Explanation:

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3 years ago
DIFFERENT PICTURE.... WHAT IS HAPPENING IN THIS PICTURES
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A dentist uses a concave mirror to examine a tooth that is 1cm in front of the mirror. The image of the tooth forms 10cm behind
iragen [17]

a) The mirror's radius of curvature will be 2.7 cm

B)  The magnification of the image will be 4.0.

<h3>What is a concave mirror?</h3>

When a hollow spherical is divided into pieces and the exterior surface of each cut portion is painted, it forms a mirror, with the inner surface reflecting the light.

From the mirror equation;

\frac{1}{p}+\frac{1}{q}  =\frac{1}{f} \\\\ \frac{1}{1}+\frac{1}{-10}  =\frac{1}{f} \\\\ \frac{1}{f} = 1-\frac{1}{10} \\\\  \frac{1}{f} = \frac{9}{10} \\\\ f= 1.1111

Hence,

The radius of curvature is twice of the focal length;

\rm R = 2f \\\\ \rm R = 2\times 1.111 \\\\ R=2.2222 \  cm

Hence, the mirror's radius of curvature will be 2.7 cm.

The magnification factor is found as;

\rm  m = \frac{-q}{p} \\\\ m = \frac{-(-10)}{1} \\\\ m = 10

Hence, the magnification of the image will be 4.0.

To learn more about the concave mirror, refer to the link;

brainly.com/question/25937699

#SPJ1

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2 years ago
Why do stars explode?
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This is known to be named supernova it a time in a stars life where it has reached it's final stage. It concludes that when stars explode supernova occurs or an tear in space is created know as a "blackhole". The star can only explode once it has survived over along period of time. 
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