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user100 [1]
3 years ago
11

If the probability of rain ia 0.87, what is the probability of NO rain? HELP

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0

An event will definitely either happen or not happen.

The total probability of it (happening or not happening) is 100%.

So if the probability of it happening is 87%, then the probability of it
NOT happening is
                                 (100% - 87%) = 13% .

You might be interested in
Need help with this problem:
Nitella [24]

Answer:

<em>Henson: 3x + y = 163</em>

<em>Garcia: 2x + 3y = 174</em>

<em>adult ticket price: $45</em>

<em>child ticket price: $28</em>

Step-by-step explanation:

Henson Family:

3 adults + 1 child; total $163

3x + y = 163

Garcia Family:

2 adults + 3 children; total $174

2x + 3y = 174

Now we solve the system of equations.

Solve the first equation (Henson Family) for y.

y = 163 - 3x

Substitute 163 - 3x for y in the second equation (Garcia Family).

2x + 3<em>y</em> = 174

2x + 3(<em>163 - 3x</em>) = 174

2x + 489 - 9x = 174

-7x + 489 = 174

-7x = -315

x = 45

Now substitute 45 for x in the first original equation and solve for y.

3x + y = 163

3(45) + y = 163

135 + y = 163

y = 28

adult ticket price: $45

child ticket price: $28

8 0
3 years ago
In the triangle below, what is the length of Ac?<br> B<br> 60°<br> 14<br> 60°<br> 60°<br> А<br> с
Katena32 [7]

Answer:

A-14

Step-by-step explanation:

All the angles of the triangle ABC are 60°.

Therefore it is an equilateral triangle.

All sides of an equilateral triangle are equal.

Hence, AC = 14

3 0
3 years ago
Consider the following dot plots.
MrRa [10]
The statement that is true is that the median pitches are 5 apart.

10,15,15,15,15,20,20,25,25
Median:15 is in the middle

10,15,15,15,20,25,25,25,25
Median: 20 is in the middle



7 0
4 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Drag the correct steps into order to solve the equation -7x + 14 = 56 for x.
Lina20 [59]

Answer:

-7x + 14 = 56

Subtract 14 both sides

-7x + 14 - 14 = 56 - 14

-7x = 42

Divide both sides by -7

(-7x)/(-7) = 42/(-7)

x = -6

3 0
3 years ago
Read 2 more answers
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