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Alex73 [517]
3 years ago
14

Differentiate the following functions with respect to x xsin x​

Physics
2 answers:
gtnhenbr [62]3 years ago
6 0

Answer:

Here is your answer

Hope it helps

Vikki [24]3 years ago
3 0

The answer is xcos x + sin x

Explanation:

d/dx (xsin x)

= x d/dx (sin x) + sin x d/dx (x)

= xcos x + sin x (1)

= xcos x + sin x

Thus, The answer is xcos x + sin x

<u>-TheUnknownScientist</u>

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A seamount is an isolated land mass rising from the ocean floor.<br> a. True<br> b. False
iris [78.8K]
The answer is A, True.
7 0
3 years ago
An above ground swimming pool of 30 ft diameter and 5 ft depth is to be filled from a garden hose (smooth interior) of length 10
STALIN [3.7K]

This question involves the concepts of dynamic pressure, volume flow rate, and flow speed.

It will take "5.1 hours" to fill the pool.

First, we will use the formula for the dynamic pressure to find out the flow speed of water:

P=\frac{1}{2}\rho v^2\\\\v=\sqrt{\frac{2P}{\rho}}

where,

v = flow speed = ?

P = Dynamic Pressure = 55 psi(\frac{6894.76\ Pa}{1\ psi}) = 379212 Pa

\rho = density of water = 1000 kg/m³

Therefore,

v=\sqrt{\frac{2(379212\ Pa)}{1000\ kg/m^3}}

v = 27.54 m/s

Now, we will use the formula for volume flow rate of water coming from the hose to find out the time taken by the pool to be filled:

\frac{V}{t} = Av\\\\t =\frac{V}{Av}

where,

t = time to fill the pool = ?

A = Area of the mouth of hose = \frac{\pi (0.015875\ m)^2}{4} = 1.98 x 10⁻⁴ m²

V = Volume of the pool = (Area of pool)(depth of pool) = A(1.524 m)

V = [\frac{\pi (9.144\ m)^2}{4}][1.524\ m] = 100.1 m³

Therefore,

t = \frac{(100.1\ m^3)}{(1.98\ x\ 10^{-4}\ m^2)(27.54\ m/s)}\\\\

<u>t = 18353.5 s = 305.9 min = 5.1 hours</u>

Learn more about dynamic pressure here:

brainly.com/question/13155610?referrer=searchResults

7 0
3 years ago
ALL OF MY POINTS FOR THIS!
scoray [572]
Newton's 2nd law of motion:

                       Force  =  (mass) x (acceleration)

                                   =  (1,127 kg) x (6 m/s² forward)

                                   =  (1,127 x 6)  newtons forward

                                   =    6,762 newtons forward
______________________________

             Momentum  =  (mass) x (speed)

                                 =   (69 kg) x (6 m/s)

                                 =      414 kg-m/s
3 0
3 years ago
Raul dug a hole in his yard to repair a water pipe. It took him 2 seconds to apply a force of 50 Newtons to push the shovel 0.25
Sergeu [11.5K]

Answer:

Option B. 6.25 J/S

Explanation:

Data obtained from the question include:

t (time) = 2secs

F (force) = 50N

d (distance) = 0.25m

P (power) =?

The power can be obtained by using the formula P = workdone/time.

P = workdone / time

P = (50 x 0.25)/ 2

P = 6.25J/s

3 0
3 years ago
Which of the following changes will increase the period of an oscillating spring mass system?
Gnoma [55]

Answer:

a. an increase in the mass on the spring.

Explanation:

T = 2π/ω = 2π/√(k/m) = 2π√(m/k)

2π is a constant

as m is in the numerator, increasing mass will increase the period.

6 0
3 years ago
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