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2 years ago

Differentiate the following functions with respect to x xsin x

Physics

2 answers:

gtnhenbr [62]2 years ago

6 0

Answer:

Here is your answer

Hope it helps

Vikki [24]2 years ago

3 0

The answer is xcos x + sin x

Explanation:

d/dx (xsin x)

= x d/dx (sin x) + sin x d/dx (x)

= xcos x + sin x (1)

= xcos x + sin x

Thus, The answer is xcos x + sin x

-TheUnknownScientist

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frozen [14]

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The percentage of the mechanical energy of the oscillator lost in each cycle is 6.72%

Explanation:

Mechanical energy (Potential energy, PE) of the oscillator is calculated as;

PE = ¹/₂KA²

During the first oscillation;

PE₁ = ¹/₂KA₁²

During the second oscillation;

A₂ = A₁ - 0.0342A₁ = 0.9658A₁

PE₂ = ¹/₂KA₂²

PE₂ = ¹/₂K (0.9658A₁)²

PE₂ = (0.9658²)¹/₂KA₁²

PE₂ = (0.9328)¹/₂KA₁²

PE₂ = 0.9328PE₁

Percentage of the mechanical energy of the oscillator lost in each cycle;

$Change \ in \ percent= \frac{PE_2 - PE_1}{PE_1} \\\\Change \ in \ percent= \frac{0.9328PE_1 -PE_1}{PE_1} *100\\\\Change \ in \ percent= \frac{-0.0672PE_1}{PE_1}*100 \\\\Change \ in \ percent= -0.0672*100\\\\Change \ in \ percent= -6.72 \ \% \\\\Loss \ in \ percent= 6.72 \ \%$