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3 years ago

Which has more energy: yellow or violet light? And why?

1 answer:

8 0

This is funny, because last year I did a project on wave lengths, but despite that; Violet light has more energy than yellow light because on the light spectrum, violet has the least wavelengths. This means they carry the most energy.

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How is the periodic table arranged ( give two ways)

vlabodo [156]

Left side metals right side non metals. arrganged in groups (columns) and periods (rows), each group tells you amount of valence electrons

7 0

3 years ago

When Wolverine’s 10-pound adamantium claws are dissolved in 100 mL of 10 M nitric acid, 10.7 grams of adamantium nitrate are rec

Mazyrski [523]

The percent yield is 71.3 %.

Explanation:

Percent yield is the measure to analyze the success percentage of any experiment .The percent yield of any experiment can be obtained by the ratio of actual or experimental value to expected or theoretical value multiplied with 100.

$Percent Yield = \frac{Experimental Outcome}{Theoretical Outcome} *100$

So, in the present problem, we have obtained 10.7 g of adamantium nitrate from Wolverine's 10 pound claws. So the actual value or the experimental value is the amount of adamantium nitrate obtained from Wolverine's claws.

Thus, the experimental outcome is 10.7 g. While we had expected to recover 15 g of adamantium nitrate. So the theoretical outcome is 15 g.

$Percent yield = \frac{10.7}{15} * 100 = 71.3 %$

Thus, the percent yield is 71.3 %.

7 0

3 years ago

Balance the following equation. <br> C + H2 + 02 → C2H60

irina1246 [14]

4C + 6H2 + O2 -> 2C2H6O

8 0

3 years ago

Read 2 more answers

True or false: A flower's only function is for reproduction

lapo4ka [179]

The answer is false. Hope this helps

3 0

3 years ago

Read 2 more answers

How many grams of CO2 are produced from 6.7 L of O2 gas at STP?

Tasya [4]

<h3>Answer:</h3>

13 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Moles
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

Using Dimensional Analysis

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<h3>Explanation:</h3>

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] 6.7 L O₂

[Solve] g O₂

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

[PT] Molar Mass of O: 16.00 g/mol

[PT] Molar Mass of C: 12.01 g/mol

Molar Mass of CO₂: 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 6.7 \ L \ O_2(\frac{1 \ mol \ O_2}{22.4 \ L \ O_2})(\frac{44.01 \ g \ O_2}{1 \ mol \ O_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 13.1637 \ g \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

13.1637 g CO₂ ≈ 13 g CO₂

5 0

3 years ago