Answer:
The forward reaction is occurring at a faster rate than the reverse reaction.
Explanation:
Reaction quotient (Q) of the given reaction is -
![Q=\frac{[NO]^{2}}{[N_{2}][O_{2}]}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%7B%5BNO%5D%5E%7B2%7D%7D%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D)
where [NO], ![[N_{2}]](https://tex.z-dn.net/?f=%5BN_%7B2%7D%5D)
and ![[O_{2}]](https://tex.z-dn.net/?f=%5BO_%7B2%7D%5D)
represents concentrations of respective species at a certain time.
Here = 0.80 M, = 0.050 M and [NO] = 0.10 M
So, 
Hence 
It means that forward reaction is faster than reverse reaction at that point. Because then only concentration of NO is higher than concentrations of and which makes Q higher than K.
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Answer:
Explanation:
Hello,
In this case, for first order reactions, we can use the following integrated rate law:
![ln(\frac{[A]}{[A]_0} )=kt](https://tex.z-dn.net/?f=ln%28%5Cfrac%7B%5BA%5D%7D%7B%5BA%5D_0%7D%20%29%3Dkt)
Thus, we compute the time as shown below:
![t=-\frac{ln(\frac{[A]}{[A]_0} )}{k}=- \frac{ln(\frac{0.220M}{0.690M} )}{0.55s^{-1}} \\\\t=-\frac{-1.14}{0.550s^{-1}}\\ \\t=2.08s](https://tex.z-dn.net/?f=t%3D-%5Cfrac%7Bln%28%5Cfrac%7B%5BA%5D%7D%7B%5BA%5D_0%7D%20%29%7D%7Bk%7D%3D-%20%5Cfrac%7Bln%28%5Cfrac%7B0.220M%7D%7B0.690M%7D%20%29%7D%7B0.55s%5E%7B-1%7D%7D%20%5C%5C%5C%5Ct%3D-%5Cfrac%7B-1.14%7D%7B0.550s%5E%7B-1%7D%7D%5C%5C%20%5C%5Ct%3D2.08s)
Best regards.
