The atom that is oxidized : Cr
The oxidizing agent : H₃PO₄
<h3>Further explanation</h3>
Reaction
2 H₃PO₄ (aq) + 2Cr(s) → 2 CrPO₄ (aq) + 3H₂(g)
Atoms undergoing a reduction reaction (decrease in oxidation number) and an oxidation reaction (increase in oxidation number)
H⁺(in H₃PO₄) =+1
H₂=0
Cr = 0
Cr³⁺(in CrPO₄ )
the oxidizing agent.⇒which undergoes a reduction reaction and oxidizes another compound/element : H₃PO₄
It is D. because the student is using a <span> thermometer and a rain gauge </span>
Ionization is a process in which an electron present in the outermost orbital of an atom gets knocked out by absorbing an appropriate amount of energy. Release of electron from a neutral atom results in the formation of a cation- a positively charged ion.
Rubidium (Rb) is an alkali metal with a valence electron configuration of 5s¹. Ionization results in the loss of this '5s' electron forming a Rb+ ion. The reaction can be expressed as:
Rb (5s¹) → Rb⁺ (5s⁰) + e⁻
Answer:
Have some attraction towards each other
Explanation:
Gases deviate from the ideal gas behavior because their molecules have forces of attraction between them. At high pressure, the molecules of gases are very close to each other so the molecular interactions start operating and these molecules do not strike the walls of the container with full impact.
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<3 simplysun
ps. I do not own any of these answers so please don't give full credit to me
