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Fynjy0 [20]
3 years ago
6

The process of removing or adding electrons is called __________.

Chemistry
1 answer:
nikdorinn [45]3 years ago
5 0
<span>The process of removing or adding electrons is called ionization </span>
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Which of the following properly describes the movement of atoms as they represent the states of matter? Atoms making liquids hav
7nadin3 [17]

Answer:

Atoms making liquids have less attraction than solids, but more than gases

Explanation:

The attraction between atoms in different molecules in a solid is very strong due to strong intermolecular forces present in a solid. However, such intermolecular forces are weaker in liquids than in solids.

This implies that the solid has higher intermolecular forces of attraction compared to gases and liquids. Based on the negligible degree of intermolecular forces between them, a gas has the weakest intermolecular forces hence the atom has very minimal interaction between them.

7 0
4 years ago
A lake has been infected by some type of new algae that is unknown. Every single day the amount of surface area that the algae t
FrozenT [24]

Answer:

It takes 86 days take to cover half of the lake

Explanation:

In the day #1, the amount of the algae is X,

In the day #2 is 2X

In the day #3 is 2*2*X = X*2²

...

In the day #n the amount of the algae is X*2^(n-1)

Assuming X = 1m³. In the day 87, the area infected was:

1m³*2^(87-1)

7.74x10²⁵m³ is the total area of the lake

the half of this amount is 3.87x10²⁵m³

The time transcurred is:

3.87x10²⁵m³ = 1m³*2^(n-1)

Multiplying for 5 in each side:

ln (3.87x10²⁵) = ln (2^(n-1))

58.9175 = n-1 * 0.6931

85 = n-1

86 = n

<h3>It takes 86 days take to cover half of the lake</h3>

4 0
3 years ago
Why are large crystals of sodium chloride used instead of small<br> crystals when making ice cream
matrenka [14]

Answer:

Sodium chloride is added to the ice to lower the freezing point of the ice. Large crystals dissolve more slowly than small crystals. This allows time for the ice cream to freeze more evenly.

Explanation:

6 0
3 years ago
A 5.22 × 10−3−mol sample of HY is dissolved in enough H2O to form 0.088 L of solution. If the pH of the solution is 2.37, what i
OleMash [197]

Answer:

3.07 × 10⁻⁴

Explanation:

Step 1: Calculate the concentration of H⁺

We will use the definition of pH.

pH = -log [H^{+} ]\\\[ [H^{+} ] = antilog -pH = antilog -2.37 = 4.27 \times 10^{-3} M

Step 2: Calculate the concentration of HY

5.22 × 10⁻³ mol of HY are dissolved in 0.088 L. The concentration of the acid (Ca) is:

Ca = \frac{5.22 \times 10^{-3} mol }{0.088L} = 0.0593M

Step 3: Calculate the acid dissociation constant (Ka)

We will use the following expression.

Ka = \frac{[H^{+}]^{2} }{Ca} = \frac{(4.27 \times 10^{-3} )^{2} }{0.0593} = 3.07 \times 10^{-4}

6 0
3 years ago
Match these items.
mr Goodwill [35]

Answer:

Here's what I get  

Explanation:

There are two methods of naming esters.

(a) Common names

alkyl alcohol + carboxylic acid ⟶ alkyl carboxylate

To form the name of an ester, you drop the alcohol and -ic acid ending from the names of the reactants.

The name of the ester consists of two words: the name of the alcohol followed by the acid name with the ending -ate.

(b) IUPAC (systematic) names

alkanol + alkanoic acid ⟶ alkyl alkanoate

To form the name of an ester, you drop the -anol and -ic acid endings from the names of the reactants.

The name of the ester consists of two words with the corresponding endings -yl and -ate.

You don't mix the common and IUPAC systems in the same name.

1. ethanol + benzoic acid ⟶ ethyl benzoate

2. benzyl alcohol + acetic acid ⟶ benzyl acetate

3. butanol + butanoic acid ⟶ butyl butanoate (IUPAC)

   butyl alcohol + butyric acid ⟶ butyl butyrate (common)

4. pentanol + propanoic acid ⟶ pentyl propanoate (IUPAC)

    n-pentyl alcohol + propionic acid ⟶ n-pentyl propionate (common)

5. isopropyl alcohol + formic acid ⟶ isopropyl formate

3 0
3 years ago
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