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VARVARA [1.3K]
3 years ago
9

A uniform marble rolls down a symmetric bowl, starting from rest atthe top of the left side. The top of each side is a distanceh

above the bottom of the bowl. The left half of the bowlis rough enough to cause the marble to roll without slipping, butthe right half has no friction because it is coated with oil.
(a) How far up the smooth side will the marblego, measured vertically from the bottom? (Use the followingvariable as necessary: h.)
H = 1Click here to preview your answer.
(b) How high would the marble go if both sides were as rough as theleft side? (Use the following variable as necessary: h.)
H = 2Click here to preview your answer.
(c) How do you account for the fact that the marble goeshigher with friction on the right side than withoutfriction?

Physics
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

A. 5/7h

B. Same height

C. See attachment below

Explanation:

Find the attachment below for better understanding.

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Calories tell you how much energy is in a food. True or False​
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Answer:True. The number of calories in a food is a measure of how much potential energy that food possesses.

Explanation:

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3 years ago
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You are given a vector in the xy plane that has a magnitude of 90.0 units and a y component of -61.0 units. A) Assuming the x co
kvasek [131]

Answer:

A) magnitude = sqrrt(147.1^2 + 61^2) = 159.2 units

B)22.5° (clockwise form -ve X axis)

Explanation:

given vector = V1 = x i - 60 j

magnitude of V1 = 90

x - component can be found out by resultant formula

90^2 = x^2 + (-60)^2

x = 67.08 = 67.1 units (3sf)

FOR THE VECTOR 80 UNITS IN -VE X DIRECTION

The X component is -80-------(1)

The Y component is 0 ---------(2)

<u>For the x- component of new added vector:</u>

(1)----------- x + 67.1 = -80

x = -147.1 = -147.1

<u>For the y- component of new added vector:</u>

<u>(</u>2)---------- y - 61  = 0

y = 61.0 (3sf)

the new added vector is  = -147.1 i + 61 j

magnitude = sqrrt(147.1^2 + 61^2) = 159.2 units

direction = arctan (61 / 147.1)

               = 22.5° (clockwise form -ve X axis)

<u />

4 0
3 years ago
An elevator is being lowered at steadily decreasing speed by a steel cable attached to an electric motor. There is no air resist
shtirl [24]

Answer:

F = W + ma  a> 0

Explanation:

For this exercise let's use Newton's second law

 we assume the upward direction as positive

          F - W = m a

          F = W + ma

          F = m (g + a)

In this case they indicate that the speed is less and less as it goes down, therefore the acceleration must be opposite to the speed, that is, the acceleration is upwards, consequently it is positive

               

We can see that since a> 0 the force F must have greater than the weight of the elevator

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A 2000 kg car accelerates from 0 to 25 m / s in 21.0 s. How much is the average power delivered by the motor? (1 hp = 746 W)
mash [69]

Answer: 40.2 hp

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The mass of the car is 2000kg.

in 21 seconds, it accelerates from 0m/s to 25m/s, so the average acceleration is:

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We know that force = mass*acceleration, then:

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Now, the Power can be written as:

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P = F*12.5m/s

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P = 2400 N*12.5m/s = 30,000 W

and we know that 1hp = 746 W

then, P = (30,000/746) hp = 40.2 hp

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3 years ago
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