A uniform marble rolls down a symmetric bowl, starting from rest atthe top of the left side. The top of each side is a distanceh
above the bottom of the bowl. The left half of the bowlis rough enough to cause the marble to roll without slipping, butthe right half has no friction because it is coated with oil.
(a) How far up the smooth side will the marblego, measured vertically from the bottom? (Use the followingvariable as necessary: h.)
H = 1Click here to preview your answer.
(b) How high would the marble go if both sides were as rough as theleft side? (Use the following variable as necessary: h.)
H = 2Click here to preview your answer.
(c) How do you account for the fact that the marble goeshigher with friction on the right side than withoutfriction?
(a) How far up the smooth side will the marblego, measured vertically from the bottom? (Use the followingvariable as necessary: h.)
H = 1Click here to preview your answer.
(b) How high would the marble go if both sides were as rough as theleft side? (Use the following variable as necessary: h.)
H = 2Click here to preview your answer.
(c) How do you account for the fact that the marble goeshigher with friction on the right side than withoutfriction?
1 answer:
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Answer:
Net force will be 4.875 N
Explanation:
We have given mass of the cart m = 1.5 kg
Initial velocity of the cart = 0.2 m/sec
And final velocity of the car = - 0.125 m/sec ( Negative direction is due to opposite direction )
Instant of time
Change in momentum is given by
Now force is given by
Net force will be 4.875 N
Answer:
F = 768 N
Explanation:
It is given that,
Speed of the elevator, v = 3.2 m/s
Grain drops into the car at the rate of 240 kg/min,
We need to find the magnitude of force needed to keep the car moving constant speed. The relation between the momentum and the force is given by :
Since, the speed is constant,
F = 768 N
So, the magnitude of force need to keep the car is 768 N. Hence, this is the required solution.