<span>Answer:
Therefore, x component: Tcos(24°) - f = 0 y component: N + Tsin(24°) - mg = 0 The two equations I get from this are: f = Tcos(24°) N = mg - Tsin(24°) In order for the crate to move, the friction force has to be greater than the normal force multiplied by the static coefficient, so... Tcos(24°) = 0.47 * (mg - Tsin(24°)) From all that I can get the equation I need for the tension, which, after some algebraic manipulation, yields: T = (mg * static coefficient) / (cos(24°) + sin(24°) * static coefficient) Then plugging in the values... T = 283.52.
Reference https://www.physicsforums.com/threads/difficulty-with-force-problems-involving-friction.111768/</span>
Answer:
1.False
2.4 E
Explanation:
1.We have to find the statement is true or false.
We know that
Time constant,
Time constant is inversely proportional to resistance R .It means when R increases then time constant decreases when R decrease then the time constant decreases.
Statement:The larger the value of R ,the longer it takes the circuit to reach its final steady- state value
It is false.
2.Energy stored in inductor,E=
When I'=2I
Then, 
Hence,the new total energy will become 4 E.
Answer:
Follows are the solution to this question:
Explanation:
In point a:
Place of particles






In point b:
when 
the Particle velocity
In point c:
Calculating the Particle acceleration:
