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bezimeni [28]
2 years ago
7

Which of the following correctly arranges the planets by the size of their diameter in increasing order?

Physics
2 answers:
sasho [114]2 years ago
8 0

Answer:

Option (C)

Explanation:

There are eight planets in our solar system.

All the planets revolves around the sun in fixed orbits.

The size of mercury is nearly 38 % of size of earth.

The size of Neptune is 388 % of size of earth.

The size of Uranus is 400 % of size of earth.

The size of Saturn is 945 % of size of earth.

The size of Jupiter is 1120 % of size of earth.

So, the increasing order of sizes of planets is

Mercury < Earth < Saturn < Jupiter.

valentinak56 [21]2 years ago
7 0
Increasing Order..
So, it's from the little one into the biggest one..

My Answer is
C: Mercury < Earth < Saturn < Jupiter

What Shape of The Earth ?
Is it Round or Flat ?
Subjective Answer..
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A simple generator is used to generate a peak output voltage of 25.0 V . The square armature consists of windings that are 7.0 c
4vir4ik [10]

Answer:

<h3>The 28 loops wound on the square armature</h3>

Explanation:

Peak output voltage \epsilon _{peak}  = 25 V

Area of square armature A = (7 \times 10^{-2} )^{2}  = 49 \times 10^{-4}

Magnetic field B = 0.490 T

Angular frequency \omega = 2\pi f = 2 \pi \times 60 = 120\pi

According to the law of electromagnetic induction,

     \epsilon _{peak} = NBA \omega

Where N = number of loops of wire.

  N = \frac{25}{49 \times 10^{-4} \times 0.49 \times 120\pi  }

  N = 27.6 ≅ 28

Thus, 28 loops of wire should be wound on the square armature.

6 0
2 years ago
a 1.2 m wire carries a current of 10.0 A in a uniform magnetic field of 0.050T. Find the magnitude of the magnetic force on the
rodikova [14]
To calculate we use the formula for a magnetic force in a current-carrying wire expressed as the product of the current, magnetic field and the length of the wire.
 F = I x L x B

where F is the force on the wire, I is the current flowing on the wire, L is the length of the wire and B is the magnetic field.

F = 10.0 A x 1.2 m x 0.050 T
F = 0.60 N
8 0
3 years ago
What determines gravitational pull
krok68 [10]

Answer

Remember that the net force on you determines how your motion changes.  The strength of the gravitational force between two objects depends on two factors, mass and distance. The Mass of the Objects The more mass two objects have, the greater. the force of gravity the masses exert on each other.

Explanation:

try to look it up on google

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6 0
3 years ago
Gretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s.
KIM [24]

Answer:

The velocity is v = 4.76 \ m/s

Explanation:

From the question we are told that

   The first distance is   d_1  =  4.0 \ km  =  4000 \ m

   The  first speed  is  v_1 =  5.0 \ m/s

    The  second distance is  d_2  =  1.0 \ km  =  1000 \ m

    The  second speed  is  v_2  =  4.0 \ m/s

Generally the time taken for first distance is  

      t_1 =  \frac{d_1 }{v_1 }

        t_1 =  \frac{4000}{5}

       t_1 =  800 \ s

The time taken for second  distance is

           t_1 =  \frac{d_2 }{v_2 }

        t_1 =  \frac{1000}{4}

       t_1 =  250 \ s

The total time is mathematically represented as

     t =  t_1 + t_2

=>   t =  800 + 250

=>    t =  1050 \ s

Generally the constant velocity that would let her finish at the same time is mathematically represented as

      v =  \frac{d_1 + d_2}{t }

=>    v =  \frac{4000 + 1000}{1050 }

=>    v = 4.76 \ m/s

7 0
3 years ago
A record player has a velocity of 33.33 RPM. How fast is the record spinning in m/s at a distance of 0.085 m from the center?
anygoal [31]

Answer:

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5 0
3 years ago
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